Invalid port number in request for secure site web page

[jfdutcher1958]

Python returns this message:

InvalidURL: nonnumeric port: '//www.a2webhosting.com:2083/frontend/x2'

in reponse to the call below ....but the port number looks
numeric ???

***************************************************************
import sys, httplib
showlines = 56
try:
servername, filename = sys.argv[1:] # cmdline args?
except:
servername, filename
= 'https://www.a2webhosting.com:2083/frontend/x2', '/index.html'

print servername, filename

 

[David M. Cooke]

Python returns this message:

InvalidURL: nonnumeric port: '//www.a2webhosting.com:2083/frontend/x2'

in reponse to the call below ....but the port number looks
numeric ???

***************************************************************
import sys, httplib
showlines = 56
try:
servername, filename = sys.argv[1:] # cmdline args?
except:
servername, filename
= 'https://www.a2webhosting.com:2083/frontend/x2', '/index.html'

print servername, filename

You've forgotten a line (the one which throws the error you've given).
But, I believe your problem is 'https://www....' is parsed as a
serverort pair: the server is https, and the port is //www..., which
of course is invalid.

I presume you're doing httplib.HTTPConnection(servername) (or
HTTPSConnection). You can't use a URL there. Usage from the docs is
like this:
Depending on what you're doing, you might be better off using the
urllib or urllib2 modules.