Java Exception Please Help

[toy]

Miller_Rabin.java:24: unreported exception java.io.IOException; must be
caught or declared to be thrown
String t = stdin.readLine();


I'm not sure how to fix this error. someone please help. I have a line
in my code that says:

String t = stdin.readLine();
s = Integer.parseInt(t);

which is the line that's generating the exception

I can' provide additional details if necessary

 

[hilz]

Miller_Rabin.java:24: unreported exception java.io.IOException; must be
caught or declared to be thrown
String t = stdin.readLine();


I'm not sure how to fix this error. someone please help. I have a line
in my code that says:

String t = stdin.readLine();
s = Integer.parseInt(t);

which is the line that's generating the exception

I can' provide additional details if necessary

This line is not throwing an exception.
This line is causing a comile error because stdin.readLine can throw an
exception at runtime, and need to be caught somewhere.
The compiler error message is telling you what to do:
the excpetion must be either caugth or declared to be thrown.
so either do this:

String t=null;
try {
t = stdin.readLine();
}catch(java.io.IOException exp){ exp.printStackTrace();}

or have the method that this line is called from throw this exception..
and then you have to catch it somewhere else....

it would help to look at the Exceptions documentation on the
java.sun.com website at this time..

HTH

 

[Roedy Green]

String t = stdin.readLine();
s = Integer.parseInt(t);

which is the line that's generating the exception

It not actually generating an exception, it just POTENTIALLY could. so
you wrap all your io code in something as simple as this:

try {

...code that does I/O...

}
catch ( IOException e )
{
System.err.println(">>>>" + e.getMessage() );
e.printStackTrace();
}

You don't normally wrap a single line in a try catch.

 

[Andrew Thompson]

Miller_Rabin.java:24: unreported exception..

Oh, way yes it was reported - over on c.l.j.help.

Please refrain from multi-posting.
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