JavaScript: conditionally invoking functions within a function

[Spartanicus]

How should functions be invoked conditionally from within a function?
This throws errors and doesn't work:

function test() {
if (0 == 0)
{
function foo();
}
if (1 == 1)
{
function bar();
}
}

Minimized test case: http://homepage.ntlworld.com/spartanicus/temp.htm

 

[Oli Filth]

Spartanicus said the following on 30/09/2005 14:15:

How should functions be invoked conditionally from within a function?
This throws errors and doesn't work:

function test() {
if (0 == 0)
{
function foo();

^
^
You don't need "function" here.

}
if (1 == 1)
{
function bar();

^
^
Nor here.

 

[Neredbojias]

With neither quill nor qualm, Spartanicus quothed:

How should functions be invoked conditionally from within a function?
This throws errors and doesn't work:

function test() {
if (0 == 0)
{
function foo();
}
if (1 == 1)
{
function bar();
}
}

Minimized test case: http://homepage.ntlworld.com/spartanicus/temp.htm

You've basically got it right.

function test() {
if (a) {
foo();
} else {
if (b) bar();
}
}

 

[Spartanicus]

You don't need "function" here.

That's the second time that I coded an error in the minimized example
that wasn't in the actual code. Fortunately I've now pinned down the
cause of the trouble with the actual script, thanks for your help.