Link Dictionary

Discussion in 'Python' started by anush shetty, Jun 11, 2007.

  1. anush shetty

    anush shetty Guest

    Hi,
    I have two dictionaries

    dict1={'B8': set(['I8', 'H8', 'B2', 'B7', 'F8', 'C9', 'G8', 'B4',
    'B5', 'B6', 'C8', 'E8', 'D8', 'B3', 'A9', 'A8', 'C7', 'B9', 'A7',
    'B1']), 'B9': set(['I9', 'H9', 'A7', 'F9', 'B3', 'B6', 'G9', 'B4',
    'B5', 'C9', 'B7', 'E9', 'B1', 'B2', 'D9', 'A9', 'A8', 'C8', 'B8',
    'C7']), 'D1': set(['F1', 'F2', 'F3', 'G1', 'I1', 'D2', 'H1', 'A1',
    'D4', 'B1', 'D8', 'D9', 'D6', 'D7', 'C1', 'D5', 'E1', 'D3', 'E3',
    'E2'])}

    and
    dict2=
    {'I6': '0', 'H9': '9', 'I2': '0', 'E8': '0', 'H3': '0', 'H7': '0',
    'I7': '3', 'I4': '0', 'H5': '0', 'F9': '0', 'G7': '5', 'G6': '9',
    'G5': '0', 'E1': '7', 'G3': '2', 'G2': '0', 'G1': '0', 'I1': '0',
    'C8': '0', 'I3': '5', 'E5': '0', 'I5': '1', 'C9': '0', 'G9': '0',
    'G8': '0', 'A1': '0', 'A3': '3', 'A2': '0', 'A5': '2', 'A4': '0',
    'A7': '6', 'A6': '0', 'C3': '1', 'C2': '0', 'C1': '0', 'E6': '0',
    'C7': '4', 'C6': '6', 'C5': '0', 'C4': '8', 'I9': '0', 'D8': '0',
    'I8': '0', 'E4': '0', 'D9': '0', 'H8': '0', 'F6': '8', 'A9': '0',
    'G4': '6', 'A8': '0', 'E7': '0', 'E3': '0', 'F1': '0', 'F2': '0',
    'F3': '6', 'F4': '7', 'F5': '0', 'E2': '0', 'F7': '2', 'F8': '0',
    'D2': '0', 'H1': '8', 'H6': '3', 'H2': '0', 'H4': '2', 'D3': '8',
    'B4': '3', 'B5': '0', 'B6': '5', 'B7': '0', 'E9': '8', 'B1': '9',
    'B2': '0', 'B3': '0', 'D6': '2', 'D7': '9', 'D4': '1', 'D5': '0',
    'B8': '0', 'B9': '1', 'D1': '0'}

    Now I want to create a dict which would have both the keys and values
    to be of the corresponding values of dict2.

    Something like this:

    Eg. The first key in dict1 i.e. B8 as 0 (0 is the value of B8 in
    dict2) mapped as set(['0','0','0',...]).

    Can anyone help me out with this.
    -
    Anush
    anush shetty, Jun 11, 2007
    #1
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  2. En Mon, 11 Jun 2007 17:24:26 -0300, anush shetty
    <> escribió:

    > Hi,
    > I have two dictionaries
    >
    > dict1={'B8': set(['I8', 'H8', 'B2', 'B7', 'F8', 'C9', 'G8', 'B4',
    > 'B5', 'B6', 'C8', 'E8', 'D8', 'B3', 'A9', 'A8', 'C7', 'B9', 'A7',
    > 'B1']), 'B9': set(['I9', 'H9', 'A7', 'F9', 'B3', 'B6', 'G9', 'B4',
    > 'B5', 'C9', 'B7', 'E9', 'B1', 'B2', 'D9', 'A9', 'A8', 'C8', 'B8',
    > 'C7']), ...
    >
    > and
    > dict2=
    > {'I6': '0', 'H9': '9', 'I2': '0', 'E8': '0', 'H3': '0', 'H7': '0',
    > 'I7': '3', 'I4': '0', 'H5': '0', 'F9': '0', 'G7': '5', 'G6': '9', [...]
    > 'B2': '0', 'B3': '0', 'D6': '2', 'D7': '9', 'D4': '1', 'D5': '0',
    > 'B8': '0', 'B9': '1', 'D1': '0'}
    >
    > Now I want to create a dict which would have both the keys and values
    > to be of the corresponding values of dict2.
    >
    > Something like this:
    >
    > Eg. The first key in dict1 i.e. B8 as 0 (0 is the value of B8 in
    > dict2) mapped as set(['0','0','0',...]).


    Sets can't have duplicate elements, so set(['0','0','0'])==set(['0'])
    And dictionaries can't have duplicate keys either.
    What do you want to do exactly? How would your desired structure look like?

    --
    Gabriel Genellina
    Gabriel Genellina, Jun 11, 2007
    #2
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  3. anush shetty

    James Stroud Guest

    anush shetty wrote:
    > Hi,
    > I have two dictionaries
    >
    > dict1={'B8': set(['I8', 'H8', 'B2', 'B7', 'F8', 'C9', 'G8', 'B4',
    > 'B5', 'B6', 'C8', 'E8', 'D8', 'B3', 'A9', 'A8', 'C7', 'B9', 'A7',
    > 'B1']), 'B9': set(['I9', 'H9', 'A7', 'F9', 'B3', 'B6', 'G9', 'B4',
    > 'B5', 'C9', 'B7', 'E9', 'B1', 'B2', 'D9', 'A9', 'A8', 'C8', 'B8',
    > 'C7']), 'D1': set(['F1', 'F2', 'F3', 'G1', 'I1', 'D2', 'H1', 'A1',
    > 'D4', 'B1', 'D8', 'D9', 'D6', 'D7', 'C1', 'D5', 'E1', 'D3', 'E3',
    > 'E2'])}
    >
    > and
    > dict2=
    > {'I6': '0', 'H9': '9', 'I2': '0', 'E8': '0', 'H3': '0', 'H7': '0',
    > 'I7': '3', 'I4': '0', 'H5': '0', 'F9': '0', 'G7': '5', 'G6': '9',
    > 'G5': '0', 'E1': '7', 'G3': '2', 'G2': '0', 'G1': '0', 'I1': '0',
    > 'C8': '0', 'I3': '5', 'E5': '0', 'I5': '1', 'C9': '0', 'G9': '0',
    > 'G8': '0', 'A1': '0', 'A3': '3', 'A2': '0', 'A5': '2', 'A4': '0',
    > 'A7': '6', 'A6': '0', 'C3': '1', 'C2': '0', 'C1': '0', 'E6': '0',
    > 'C7': '4', 'C6': '6', 'C5': '0', 'C4': '8', 'I9': '0', 'D8': '0',
    > 'I8': '0', 'E4': '0', 'D9': '0', 'H8': '0', 'F6': '8', 'A9': '0',
    > 'G4': '6', 'A8': '0', 'E7': '0', 'E3': '0', 'F1': '0', 'F2': '0',
    > 'F3': '6', 'F4': '7', 'F5': '0', 'E2': '0', 'F7': '2', 'F8': '0',
    > 'D2': '0', 'H1': '8', 'H6': '3', 'H2': '0', 'H4': '2', 'D3': '8',
    > 'B4': '3', 'B5': '0', 'B6': '5', 'B7': '0', 'E9': '8', 'B1': '9',
    > 'B2': '0', 'B3': '0', 'D6': '2', 'D7': '9', 'D4': '1', 'D5': '0',
    > 'B8': '0', 'B9': '1', 'D1': '0'}
    >
    > Now I want to create a dict which would have both the keys and values
    > to be of the corresponding values of dict2.
    >
    > Something like this:
    >
    > Eg. The first key in dict1 i.e. B8 as 0 (0 is the value of B8 in
    > dict2) mapped as set(['0','0','0',...]).
    >
    > Can anyone help me out with this.
    > -
    > Anush
    >


    new_dict = {}
    for akey, aset in dict1.items():
    new_dict[akey] = sum(int(dict2[k]) for k in aset)

    James
    James Stroud, Jun 11, 2007
    #3
  4. anush shetty

    anush shetty Guest

    On Jun 12, 2:10 am, James Stroud <> wrote:
    > anush shetty wrote:
    > > Hi,
    > > I have two dictionaries

    >
    > > dict1={'B8': set(['I8', 'H8', 'B2', 'B7', 'F8', 'C9', 'G8', 'B4',
    > > 'B5', 'B6', 'C8', 'E8', 'D8', 'B3', 'A9', 'A8', 'C7', 'B9', 'A7',
    > > 'B1']), 'B9': set(['I9', 'H9', 'A7', 'F9', 'B3', 'B6', 'G9', 'B4',
    > > 'B5', 'C9', 'B7', 'E9', 'B1', 'B2', 'D9', 'A9', 'A8', 'C8', 'B8',
    > > 'C7']), 'D1': set(['F1', 'F2', 'F3', 'G1', 'I1', 'D2', 'H1', 'A1',
    > > 'D4', 'B1', 'D8', 'D9', 'D6', 'D7', 'C1', 'D5', 'E1', 'D3', 'E3',
    > > 'E2'])}

    >
    > > and
    > > dict2=
    > > {'I6': '0', 'H9': '9', 'I2': '0', 'E8': '0', 'H3': '0', 'H7': '0',
    > > 'I7': '3', 'I4': '0', 'H5': '0', 'F9': '0', 'G7': '5', 'G6': '9',
    > > 'G5': '0', 'E1': '7', 'G3': '2', 'G2': '0', 'G1': '0', 'I1': '0',
    > > 'C8': '0', 'I3': '5', 'E5': '0', 'I5': '1', 'C9': '0', 'G9': '0',
    > > 'G8': '0', 'A1': '0', 'A3': '3', 'A2': '0', 'A5': '2', 'A4': '0',
    > > 'A7': '6', 'A6': '0', 'C3': '1', 'C2': '0', 'C1': '0', 'E6': '0',
    > > 'C7': '4', 'C6': '6', 'C5': '0', 'C4': '8', 'I9': '0', 'D8': '0',
    > > 'I8': '0', 'E4': '0', 'D9': '0', 'H8': '0', 'F6': '8', 'A9': '0',
    > > 'G4': '6', 'A8': '0', 'E7': '0', 'E3': '0', 'F1': '0', 'F2': '0',
    > > 'F3': '6', 'F4': '7', 'F5': '0', 'E2': '0', 'F7': '2', 'F8': '0',
    > > 'D2': '0', 'H1': '8', 'H6': '3', 'H2': '0', 'H4': '2', 'D3': '8',
    > > 'B4': '3', 'B5': '0', 'B6': '5', 'B7': '0', 'E9': '8', 'B1': '9',
    > > 'B2': '0', 'B3': '0', 'D6': '2', 'D7': '9', 'D4': '1', 'D5': '0',
    > > 'B8': '0', 'B9': '1', 'D1': '0'}

    >
    > > Now I want to create a dict which would have both the keys and values
    > > to be of the corresponding values of dict2.

    >
    > > Something like this:

    >
    > > Eg. The first key in dict1 i.e. B8 as 0 (0 is the value of B8 in
    > > dict2) mapped as set(['0','0','0',...]).

    >
    > > Can anyone help me out with this.
    > > -
    > > Anush

    >
    > new_dict = {}
    > for akey, aset in dict1.items():
    > new_dict[akey] = sum(int(dict2[k]) for k in aset)
    >
    > James



    So there is no way I can represent all the duplicates right.

    So is there any solution where I could take the values of dictionary
    and represent them separately?

    -
    Anush
    anush shetty, Jun 11, 2007
    #4
  5. anush shetty

    anush shetty Guest

    On Jun 12, 1:50 am, "Gabriel Genellina" <>
    wrote:
    > En Mon, 11 Jun 2007 17:24:26 -0300, anush shetty
    > <> escribió:
    >
    >
    >
    > > Hi,
    > > I have two dictionaries

    >
    > > dict1={'B8': set(['I8', 'H8', 'B2', 'B7', 'F8', 'C9', 'G8', 'B4',
    > > 'B5', 'B6', 'C8', 'E8', 'D8', 'B3', 'A9', 'A8', 'C7', 'B9', 'A7',
    > > 'B1']), 'B9': set(['I9', 'H9', 'A7', 'F9', 'B3', 'B6', 'G9', 'B4',
    > > 'B5', 'C9', 'B7', 'E9', 'B1', 'B2', 'D9', 'A9', 'A8', 'C8', 'B8',
    > > 'C7']), ...

    >
    > > and
    > > dict2=
    > > {'I6': '0', 'H9': '9', 'I2': '0', 'E8': '0', 'H3': '0', 'H7': '0',
    > > 'I7': '3', 'I4': '0', 'H5': '0', 'F9': '0', 'G7': '5', 'G6': '9', [...]
    > > 'B2': '0', 'B3': '0', 'D6': '2', 'D7': '9', 'D4': '1', 'D5': '0',
    > > 'B8': '0', 'B9': '1', 'D1': '0'}

    >
    > > Now I want to create a dict which would have both the keys and values
    > > to be of the corresponding values of dict2.

    >
    > > Something like this:

    >
    > > Eg. The first key in dict1 i.e. B8 as 0 (0 is the value of B8 in
    > > dict2) mapped as set(['0','0','0',...]).

    >
    > Sets can't have duplicate elements, so set(['0','0','0'])==set(['0'])
    > And dictionaries can't have duplicate keys either.
    > What do you want to do exactly? How would your desired structure look like?
    >
    > --
    > Gabriel Genellina


    Need it for a verification of the puzzle. It has duplicate values. But
    there is any way where i could represent them with duplicates

    -
    Anush
    anush shetty, Jun 11, 2007
    #5
  6. anush shetty

    Paddy Guest

    On Jun 11, 10:19 pm, anush shetty <> wrote:
    > On Jun 12, 2:10 am, James Stroud <> wrote:
    >
    >
    >
    > > anush shetty wrote:
    > > > Hi,
    > > > I have two dictionaries

    >
    > > > dict1={'B8': set(['I8', 'H8', 'B2', 'B7', 'F8', 'C9', 'G8', 'B4',
    > > > 'B5', 'B6', 'C8', 'E8', 'D8', 'B3', 'A9', 'A8', 'C7', 'B9', 'A7',
    > > > 'B1']), 'B9': set(['I9', 'H9', 'A7', 'F9', 'B3', 'B6', 'G9', 'B4',
    > > > 'B5', 'C9', 'B7', 'E9', 'B1', 'B2', 'D9', 'A9', 'A8', 'C8', 'B8',
    > > > 'C7']), 'D1': set(['F1', 'F2', 'F3', 'G1', 'I1', 'D2', 'H1', 'A1',
    > > > 'D4', 'B1', 'D8', 'D9', 'D6', 'D7', 'C1', 'D5', 'E1', 'D3', 'E3',
    > > > 'E2'])}

    >
    > > > and
    > > > dict2=
    > > > {'I6': '0', 'H9': '9', 'I2': '0', 'E8': '0', 'H3': '0', 'H7': '0',
    > > > 'I7': '3', 'I4': '0', 'H5': '0', 'F9': '0', 'G7': '5', 'G6': '9',
    > > > 'G5': '0', 'E1': '7', 'G3': '2', 'G2': '0', 'G1': '0', 'I1': '0',
    > > > 'C8': '0', 'I3': '5', 'E5': '0', 'I5': '1', 'C9': '0', 'G9': '0',
    > > > 'G8': '0', 'A1': '0', 'A3': '3', 'A2': '0', 'A5': '2', 'A4': '0',
    > > > 'A7': '6', 'A6': '0', 'C3': '1', 'C2': '0', 'C1': '0', 'E6': '0',
    > > > 'C7': '4', 'C6': '6', 'C5': '0', 'C4': '8', 'I9': '0', 'D8': '0',
    > > > 'I8': '0', 'E4': '0', 'D9': '0', 'H8': '0', 'F6': '8', 'A9': '0',
    > > > 'G4': '6', 'A8': '0', 'E7': '0', 'E3': '0', 'F1': '0', 'F2': '0',
    > > > 'F3': '6', 'F4': '7', 'F5': '0', 'E2': '0', 'F7': '2', 'F8': '0',
    > > > 'D2': '0', 'H1': '8', 'H6': '3', 'H2': '0', 'H4': '2', 'D3': '8',
    > > > 'B4': '3', 'B5': '0', 'B6': '5', 'B7': '0', 'E9': '8', 'B1': '9',
    > > > 'B2': '0', 'B3': '0', 'D6': '2', 'D7': '9', 'D4': '1', 'D5': '0',
    > > > 'B8': '0', 'B9': '1', 'D1': '0'}

    >
    > > > Now I want to create a dict which would have both the keys and values
    > > > to be of the corresponding values of dict2.

    >
    > > > Something like this:

    >
    > > > Eg. The first key in dict1 i.e. B8 as 0 (0 is the value of B8 in
    > > > dict2) mapped as set(['0','0','0',...]).

    >
    > > > Can anyone help me out with this.
    > > > -
    > > > Anush

    >
    > > new_dict = {}
    > > for akey, aset in dict1.items():
    > > new_dict[akey] = sum(int(dict2[k]) for k in aset)

    >
    > > James

    >
    > So there is no way I can represent all the duplicates right.
    >
    > So is there any solution where I could take the values of dictionary
    > and represent them separately?
    >
    > -
    > Anush


    I use lists instead of your dict1 but preserve your mapping dict2:

    data = [
    ['B8',
    ['I8', 'H8', 'B2', 'B7', 'F8',
    'C9', 'G8', 'B4', 'B5', 'B6',
    'C8', 'E8', 'D8', 'B3', 'A9',
    'A8', 'C7', 'B9', 'A7', 'B1']],
    ['B9',
    ['I9', 'H9', 'A7', 'F9', 'B3',
    'B6', 'G9', 'B4', 'B5', 'C9',
    'B7', 'E9', 'B1', 'B2', 'D9',
    'A9', 'A8', 'C8', 'B8', 'C7']],
    ['D1',
    ['F1', 'F2', 'F3', 'G1', 'I1',
    'D2', 'H1', 'A1', 'D4', 'B1',
    'D8', 'D9', 'D6', 'D7', 'C1',
    'D5', 'E1', 'D3', 'E3', 'E2']]]

    dict2= {
    'I6': '0', 'H9': '9', 'I2': '0', 'E8': '0', 'H3': '0', 'H7': '0',
    'I7': '3', 'I4': '0', 'H5': '0', 'F9': '0', 'G7': '5', 'G6': '9',
    'G5': '0', 'E1': '7', 'G3': '2', 'G2': '0', 'G1': '0', 'I1': '0',
    'C8': '0', 'I3': '5', 'E5': '0', 'I5': '1', 'C9': '0', 'G9': '0',
    'G8': '0', 'A1': '0', 'A3': '3', 'A2': '0', 'A5': '2', 'A4': '0',
    'A7': '6', 'A6': '0', 'C3': '1', 'C2': '0', 'C1': '0', 'E6': '0',
    'C7': '4', 'C6': '6', 'C5': '0', 'C4': '8', 'I9': '0', 'D8': '0',
    'I8': '0', 'E4': '0', 'D9': '0', 'H8': '0', 'F6': '8', 'A9': '0',
    'G4': '6', 'A8': '0', 'E7': '0', 'E3': '0', 'F1': '0', 'F2': '0',
    'F3': '6', 'F4': '7', 'F5': '0', 'E2': '0', 'F7': '2', 'F8': '0',
    'D2': '0', 'H1': '8', 'H6': '3', 'H2': '0', 'H4': '2', 'D3': '8',
    'B4': '3', 'B5': '0', 'B6': '5', 'B7': '0', 'E9': '8', 'B1': '9',
    'B2': '0', 'B3': '0', 'D6': '2', 'D7': '9', 'D4': '1', 'D5': '0',
    'B8': '0', 'B9': '1', 'D1': '0'}

    dout = [[dict2,[dict2[k] for k in j]]
    for i,j in data]
    print dout

    - Paddy.
    Paddy, Jun 11, 2007
    #6
  7. anush shetty

    Paddy Guest


    >
    > dout = [[dict2,[dict2[k] for k in j]]
    > for i,j in data]
    > print dout
    >
    > - Paddy.


    Working from your original dict1:

    dout = [[dict2, [dict2[k] for k in setvalue]]
    for i,setvalue in dict1.iteritems()]

    - Paddy
    Paddy, Jun 11, 2007
    #7
  8. anush shetty

    James Stroud Guest

    anush shetty wrote:
    > On Jun 12, 2:10 am, James Stroud <> wrote:
    >
    >>anush shetty wrote:
    >>
    >>>Hi,
    >>>I have two dictionaries

    >>
    >>> dict1={'B8': set(['I8', 'H8', 'B2', 'B7', 'F8', 'C9', 'G8', 'B4',
    >>>'B5', 'B6', 'C8', 'E8', 'D8', 'B3', 'A9', 'A8', 'C7', 'B9', 'A7',
    >>>'B1']), 'B9': set(['I9', 'H9', 'A7', 'F9', 'B3', 'B6', 'G9', 'B4',
    >>>'B5', 'C9', 'B7', 'E9', 'B1', 'B2', 'D9', 'A9', 'A8', 'C8', 'B8',
    >>>'C7']), 'D1': set(['F1', 'F2', 'F3', 'G1', 'I1', 'D2', 'H1', 'A1',
    >>>'D4', 'B1', 'D8', 'D9', 'D6', 'D7', 'C1', 'D5', 'E1', 'D3', 'E3',
    >>>'E2'])}

    >>
    >>>and
    >>>dict2=
    >>>{'I6': '0', 'H9': '9', 'I2': '0', 'E8': '0', 'H3': '0', 'H7': '0',
    >>>'I7': '3', 'I4': '0', 'H5': '0', 'F9': '0', 'G7': '5', 'G6': '9',
    >>>'G5': '0', 'E1': '7', 'G3': '2', 'G2': '0', 'G1': '0', 'I1': '0',
    >>>'C8': '0', 'I3': '5', 'E5': '0', 'I5': '1', 'C9': '0', 'G9': '0',
    >>>'G8': '0', 'A1': '0', 'A3': '3', 'A2': '0', 'A5': '2', 'A4': '0',
    >>>'A7': '6', 'A6': '0', 'C3': '1', 'C2': '0', 'C1': '0', 'E6': '0',
    >>>'C7': '4', 'C6': '6', 'C5': '0', 'C4': '8', 'I9': '0', 'D8': '0',
    >>>'I8': '0', 'E4': '0', 'D9': '0', 'H8': '0', 'F6': '8', 'A9': '0',
    >>>'G4': '6', 'A8': '0', 'E7': '0', 'E3': '0', 'F1': '0', 'F2': '0',
    >>>'F3': '6', 'F4': '7', 'F5': '0', 'E2': '0', 'F7': '2', 'F8': '0',
    >>>'D2': '0', 'H1': '8', 'H6': '3', 'H2': '0', 'H4': '2', 'D3': '8',
    >>>'B4': '3', 'B5': '0', 'B6': '5', 'B7': '0', 'E9': '8', 'B1': '9',
    >>>'B2': '0', 'B3': '0', 'D6': '2', 'D7': '9', 'D4': '1', 'D5': '0',
    >>>'B8': '0', 'B9': '1', 'D1': '0'}

    >>
    >>>Now I want to create a dict which would have both the keys and values
    >>>to be of the corresponding values of dict2.

    >>
    >>>Something like this:

    >>
    >>>Eg. The first key in dict1 i.e. B8 as 0 (0 is the value of B8 in
    >>>dict2) mapped as set(['0','0','0',...]).

    >>
    >>>Can anyone help me out with this.
    >>>-
    >>>Anush

    >>
    >>new_dict = {}
    >>for akey, aset in dict1.items():
    >> new_dict[akey] = sum(int(dict2[k]) for k in aset)
    >>
    >>James

    >
    >
    >
    > So there is no way I can represent all the duplicates right.
    >
    > So is there any solution where I could take the values of dictionary
    > and represent them separately?
    >
    > -
    > Anush
    >


    Just leave off the sum and turn the generator into a list comprehension:

    new_dict = {}
    for akey, aset in dict1.items():
    new_dict[akey] = [dict2[k] for k in aset]

    James
    James Stroud, Jun 11, 2007
    #8
  9. anush shetty

    anush shetty Guest


    >
    > Working from your original dict1:
    >
    > dout = [[dict2, [dict2[k] for k in setvalue]]
    > for i,setvalue in dict1.iteritems()]
    >
    > - Paddy



    I dont think this works.
    anush shetty, Jun 11, 2007
    #9
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