lost. Help

[Bill Cunningham]

In a previous post I mentioned a beautifully working simple function
called out with this prototype:

int out (int n,char *buffer);

Great. But how would I handle the command line? I have arrays and sub-arrays
char *argv[] and argc.

int main (int argc, char *argv[]) {
/* In one of these two parameters I am going to have to take a
string and send it back. What I want is a perfect version of puts. Which of
these two parameters would take a single string like "hello world\n" and
print it adding newline like puts ? I'm going to need extra functions. Maybe
atoi and others. */

return puts(string); /* from argc or argv[] */

Am I making sense ?

Bill

 

[Lew Pitcher]

In a previous post I mentioned a beautifully working simple function
called out with this prototype:

int out (int n,char *buffer);

Nice prototype. What sort of data do 'n' and 'buffer' represent?

Great. But how would I handle the command line? I have arrays and
sub-arrays char *argv[] and argc.

int main (int argc, char *argv[]) {
/* In one of these two parameters I am going to have to take a
string

Only one of those parameters is capable of presenting a "string".

and send it back.

Back where?

What I want is a perfect version of puts. Which
of these two parameters would take a single string like "hello world\n"
and print it adding newline like puts ? I'm going to need extra functions.
Maybe atoi and others. */

return puts(string); /* from argc or argv[] */

Am I making sense ?

No and yes.

You want one of the occurrences of argv[]. /Which/ occurrence depends on
a) the order of argument data as provided by the environment (the "command
line" or it's equivalent, and your "usage" for your program), and
b) the value of argc

argc will contain a count of the number of valid argv[] elements, or 0

if argc > 0
argv[0] will be a pointer to a string containing the "program name",
whatever /that/ is
argv[1] through argv[argc-1] will be pointers to strings, each string
being provided by your execution environment. Typically, argv[1] is
the first string provided on the commandline, argv[2] is the 2nd, etc.
argv[argc] will be NULL

For example, using the code below...

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
printf("argc == %d\n",argc);

if (argc == 0)
puts("Execution environment does not support argument strings");
else
{
int arg;

for (arg = 0; arg <= argc; ++arg)
{
printf("argv[%d] = ",arg);
if (argv[arg] == NULL)
puts("NULL");
else
printf("\"%s\"\n",argv[arg]);
}
}

return EXIT_SUCCESS;
}

In my execution environment, we see that

~/code/tmp $ args
argc == 1
argv[0] = "args"
argv[1] = NULL


And that

~/code/tmp $ args a b c "d E fgh" i jkl
argc == 7
argv[0] = "args"
argv[1] = "a"
argv[2] = "b"
argv[3] = "c"
argv[4] = "d E fgh"
argv[5] = "i"
argv[6] = "jkl"
argv[7] = NULL


--
Lew Pitcher

Master Codewright & JOAT-in-training | Registered Linux User #112576
http://pitcher.digitalfreehold.ca/ | GPG public key available by request
---------- Slackware - Because I know what I'm doing. ------

 

[Bill Cunningham]

Nice prototype. What sort of data do 'n' and 'buffer' represent?

Great. But how would I handle the command line? I have arrays and
sub-arrays char *argv[] and argc.

int main (int argc, char *argv[]) {
/* In one of these two parameters I am going to have to take a
string

Only one of those parameters is capable of presenting a "string".

and send it back.

Back where?

What I want is a perfect version of puts. Which
of these two parameters would take a single string like "hello world\n"
and print it adding newline like puts ? I'm going to need extra
functions.
Maybe atoi and others. */

return puts(string); /* from argc or argv[] */

Am I making sense ?

No and yes.

You want one of the occurrences of argv[]. /Which/ occurrence depends on
a) the order of argument data as provided by the environment (the "command
line" or it's equivalent, and your "usage" for your program), and
b) the value of argc

argc will contain a count of the number of valid argv[] elements, or 0

if argc > 0
argv[0] will be a pointer to a string containing the "program name",
whatever /that/ is
argv[1] through argv[argc-1] will be pointers to strings, each string
being provided by your execution environment. Typically, argv[1] is
the first string provided on the commandline, argv[2] is the 2nd, etc.
argv[argc] will be NULL

For example, using the code below...

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
printf("argc == %d\n",argc);

if (argc == 0)
puts("Execution environment does not support argument strings");
else
{
int arg;

for (arg = 0; arg <= argc; ++arg)
{
printf("argv[%d] = ",arg);
if (argv[arg] == NULL)
puts("NULL");
else
printf("\"%s\"\n",argv[arg]);
}
}

return EXIT_SUCCESS;
}

In my execution environment, we see that

~/code/tmp $ args
argc == 1
argv[0] = "args"
argv[1] = NULL


And that

~/code/tmp $ args a b c "d E fgh" i jkl
argc == 7
argv[0] = "args"
argv[1] = "a"
argv[2] = "b"
argv[3] = "c"
argv[4] = "d E fgh"
argv[5] = "i"
argv[6] = "jkl"
argv[7] = NULL

Lew alot of your code went over my head. Let me write a simple function
of what I want.

int out(char * buffer) {
return puts(buffer);
}

Out just behaves as puts. Nice function. But I want to call from command
line in linux enviornment.

out "hello world" /*< stdin*/
/*stdout>*/ hello world /*with \n from puts */

So I know I will have to begin like this.

int main (int argc,char **argv) {

puts will have to be in the body somewhere and argc and argv control
somewhere. Also since main returns int I think I would have to convert the
char* into an int. It's what to do with argc and argv[] that I don't know
what to do.

Bill

 

[Bill Cunningham]

Lew alot of your code went over my head. Let me write a simple function

of what I want.

Ok you're demonstrating how argc and argv works.

Bill