Member vs. non-member operator overload disambiguation

[W Karas]

Suppose an operator invocation matches a free-standing operator and a member operator of the class of the first argument equally well. Is this ambiguous? Or, does the Standard give member operators higher or lower precedence?

Related question: Does the Standard give higher or lower precedence to friend functions compared to non-friend functions?

 

[Victor Bazarov]

Suppose an operator invocation matches a free-standing operator and a
member operator of the class of the first argument equally well. Is
this ambiguous? Or, does the Standard give member operators higher
or lower precedence?

From what I could find, no preference is given. Ambiguous, most likely.

Related question: Does the Standard give higher or lower precedence
to friend functions compared to non-friend functions?

Same thing.

Why are you asking? Do you have a concrete code for which the behavior
of your compiler is suspect?

V

 

[W Karas]

From what I could find, no preference is given. Ambiguous, most likely.

Thanks, interesting.

Same thing.



Why are you asking? Do you have a concrete code for which the behavior

of your compiler is suspect?

Yes but it's proprietary. Someone gave it to me and said it was working, but I got compile errors.

 

[Victor Bazarov]

Yes but it's proprietary. Someone gave it to me and said it was
working, but I got compile errors.

Proprietary or not, you *could* rewrite the code and remove all
identifiable and copyright-protected features from it. If you are
interested in more details regarding the compiler behavior or whether
some particular code constructs are legal or not, we *need* to see the
code. Again, rewrite it, distill it, sterilize it. Leave only the
parts that give you the same error, then post it.

V