Multi-dimensional heap array

[JKop]

int main()
{
int normal[2][3];

int (&on_the_heap)[2][3] = *new int[2][3];
}


My operator precendence may be wrong in the above.


-JKop

 

[Derrick Coetzee]

int (&on_the_heap)[2][3] = *new int[2][3];

There is no language construct for dynamically allocating
multidimensional arrays. See the comp.lang.c FAQ question 6.16 and
related questions:

http://www.eskimo.com/~scs/C-faq/q6.16.html

(Substitute new for malloc appropriately)

 

[JKop]

Derrick Coetzee posted:

int (&on_the_heap)[2][3] = *new int[2][3];

There is no language construct for dynamically allocating
multidimensional arrays. See the comp.lang.c FAQ question 6.16 and
related questions:

http://www.eskimo.com/~scs/C-faq/q6.16.html

(Substitute new for malloc appropriately)

I've done it before. I used a reference or a pointer to a
multidimensional array I believe.

Something along the lines of:

int k[8];

int (&r)[2] = k;

r[0][1] = 1;
r[0][2] = 2;
r[0][3] = 3;
r[0][4] = 4;
r[1][1] = 5;
r[1][2] = 6;

//and so on


-JKop

 

[Ioannis Vranos]

int main()
{
int normal[2][3];

int (&on_the_heap)[2][3] = *new int[2][3];
}


My operator precendence may be wrong in the above.

int (*p)[3]=new int[2][3];

// ...


delete[] p;






Regards,

Ioannis Vranos

http://www23.brinkster.com/noicys

 

[Ioannis Vranos]

int (&on_the_heap)[2][3] = *new int[2][3];

There is no language construct for dynamically allocating
multidimensional arrays.

What?





See the comp.lang.c FAQ question 6.16 and
related questions:

http://www.eskimo.com/~scs/C-faq/q6.16.html

It is C++ here, not C. But I just checked that FAQ. Who wrote that CRAP?

Even the casts it has in malloc are not needed in C!


In any case in C it can be done:


#include <stdlib.h>

/* ... */

int (*p)[3]=malloc(2*sizeof(*p));

/* ... */

free(p);






Regards,

Ioannis Vranos

http://www23.brinkster.com/noicys

 

[Andre Kostur]

Derrick Coetzee posted:

int (&on_the_heap)[2][3] = *new int[2][3];

There is no language construct for dynamically allocating
multidimensional arrays. See the comp.lang.c FAQ question 6.16 and
related questions:

http://www.eskimo.com/~scs/C-faq/q6.16.html

(Substitute new for malloc appropriately)

I've done it before. I used a reference or a pointer to a
multidimensional array I believe.

Something along the lines of:

int k[8];

int (&r)[2] = k;

r[0][1] = 1;
r[0][2] = 2;
r[0][3] = 3;
r[0][4] = 4;
r[1][1] = 5;
r[1][2] = 6;

//and so on

And what does this have to do with dynamically allocating
multidimensional arrays?

 

[JKop]

Andre Kostur posted:

Derrick Coetzee posted:

JKop wrote:
int (&on_the_heap)[2][3] = *new int[2][3];

There is no language construct for dynamically allocating
multidimensional arrays. See the comp.lang.c FAQ question 6.16 and
related questions:

http://www.eskimo.com/~scs/C-faq/q6.16.html

(Substitute new for malloc appropriately)

I've done it before. I used a reference or a pointer to a
multidimensional array I believe.

Something along the lines of:

int k[8];

int (&r)[2] = k;

r[0][1] = 1;
r[0][2] = 2;
r[0][3] = 3;
r[0][4] = 4;
r[1][1] = 5;
r[1][2] = 6;

//and so on

And what does this have to do with dynamically allocating
multidimensional arrays?

Do I have to do EVERYTHING myself?! Just make k dynamically
allocated:

int& k = *new int[8];

 

[Ioannis Vranos]

It is C++ here, not C. But I just checked that FAQ. Who wrote that CRAP?

Even the casts it has in malloc are not needed in C!


In any case in C it can be done:


#include <stdlib.h>

/* ... */

int (*p)[3]=malloc(2*sizeof(*p));

/* ... */

free(p);

The above implies that one dimension must be known.






Regards,

Ioannis Vranos

http://www23.brinkster.com/noicys

 

[Old Wolf]

int (&on_the_heap)[2][3] = *new int[2][3];

There is no language construct for dynamically allocating
multidimensional arrays.

Crap, as demonstrated by JKop's example

It is C++ here, not C. But I just checked that FAQ. Who wrote that CRAP?

Even the casts it has in malloc are not needed in C!

That's been fixed in the text version of the faq (nobody bothers
to update the HTML version).