Need help

[bigmoviebuff]

Hi guys does any of you guys have this c++ program .
I need the program to input a string and accept a word number and
print this pattern.


Input) This is a message
Input)4

output) s
ssa
essag
message
essag
ssa
s

and if it is a even word for example golden then the output is


ld
olde
golden
olde
ld


Please can any of you guys write this program for me .

 

[Zeppe]

Please can any of you guys write this program for me .

no.

 

[Triple-DES]

Hi guys does any of you guys have this c++ program .
I need the program to input a string and accept a word number and
print this pattern.

Input) This is a message
Input)4

output)                          s
                                  ssa
                                 essag
                               message
                                 essag
                                   ssa
                                     s

and if it is a even word for example golden then the output is

                                   ld
                                 olde
                               golden
                                 olde
                                   ld

Please can any of you guys write this program for me .

Sure, here you go:

#include <iostream>
#include <string>
#include <vector>
#include <algorithm>
using namespace std;
ostream& o = cout;
istream& i = cin;
typedef string s;
typedef vector<s> v;
typedef s::iterator si;
typedef size_t t;
#define b_ begin()
#define e_ end()
int main() {
s s_; v v_; t n;
getline(i,s_);
i>>n;
while(--n) s_ = s(find(s_.b_, s_.e_,' ')+1,s_.e_);
s_ = s(s_.b_,find(s_.b_,s_.e_,' '));
t d = 0u;
t ll = s_.size();
for(t l = ((ll ^ 1u) & 1u) + 1; l <= ll {
si b = s_.b_ + (ll - l) / 2;
o<< s(b, b + l) << "\n";
l += 2 - d;
if(l >= ll) d = 4u;
}}

 

[osmium]

Hi guys does any of you guys have this c++ program .
I need the program to input a string and accept a word number and
print this pattern.


Input) This is a message
Input)4

output) s
ssa
essag
message
essag
ssa
s

and if it is a even word for example golden then the output is


ld
olde
golden
olde
ld

There are two main parts to the question. Isolate a particular word and then
print that word in the funny pattern required. There are two kinds of
printing, depending on how many characters are in the word. Start by
writing a program that will get the two inputs from a user. isolate the
desired word and pass that word to a function *to be defined* (by you) that
will do the printing. For earrly testing, simply print the word in that
function.

 

[red floyd]

Hi guys does any of you guys have this c++ program .
I need the program to input a string and accept a word number and
print this pattern.

[redacted]

Hi bigmoviebuff, you can find your program here:

http://www.parashift.com/c++-faq-lite/how-to-post.html#faq-5.2

 

[P. Lepin]

I need the program to input a string and accept a word number and
print this pattern.

output) s
ssa
essag
message
essag
ssa
s

Please can any of you guys write this program for me .

Sure, why not.

#include <stdexcept>
#include <string>
#include <iostream>
#include <istream>
#include <ostream>
#include <sstream>
using namespace std;
#define m 1<<8
#define si signed int
#define sz size
#define sb substr
#define st string
#define ss istringstream
#define cc(y) c<t,(l-y>0?l-y:1)>
template<class t,si l> class c{
public:t s_,z_;cc(2)*t_;si b_,l_;
static t*p(t s){t x;x=l==1?s:*cc(1):(s);
return new t(t(x.sz()<l?" ":"")+x);}
c(t s,si n=0)
:s_(s),z_(*c<t,m>:(s)),b_(1),l_(!n?s.sz():n){
try{t_=new cc(2)(s_.sb(1,s_.sz()-2),l_);}
catch(out_of_range e){b_=!b_;}}
virtual ~c(){if(b_)delete t_;}
void operator[](si x){(*this)(x);if(b_)(*t_)[!b_];}
void operator()(si x){if(b_&&x)(*t_)(x);
if(l_!=l)cout<<z_.sb(z_.sz()-l_)<<endl;}};
int main(){st g,w;getline(cin,g);si i;cin>>i;ss k(g);
while(i--){k>>w;}c<st,m>o(w);o[1];}

There you go.

 

[jason.cipriani]

Sure, why not.

I see; so that's the way you want to be. Fine.

*cracks knuckles*

#include <stdio.h>
int main(int Z,char*_,int N){switch(Z){case 0:if(*_){putchar(
main(Z-1,"double f;switch{}0x53*DEBUG=1+9.%|> !+./1256789:I_"
"abcdefghklmn""oprstuwy",*_));return main(Z,1+_,N);}return 0;
case -1:if(N==*_)return 36[_+Z] ;else return main(Z,_-Z,N);
}return main(Z-Z,"cd0D5{.5xd=GdU>dD=U5|=+Ed{.dD..1tll*+=%19b"
"*==*B5b0=Ul*+=%1l0=U1bB{G*b0uul}+=|95h3+Ul.D+5{xl3xw;seif{w"
"3;f3 edo",N);}

That's C, mind you.

Jason

 

[InsainFreak101]

If your newer to c++, I would start with the word, then delete the the
end letters and display them above and below the original word until
the length of the string is 1 or 2.

 

[Pavel Lepin]

Sure, why not.

I see; so that's the way you want to be. Fine.

*cracks knuckles*

#include <stdio.h>
int main(int Z,char*_,int N){switch(Z){case
0:if(*_){putchar( main(Z-1,"double
f;switch{}0x53*DEBUG=1+9.%|> !+./1256789:I_"
"abcdefghklmn""oprstuwy",*_));return main(Z,1+_,N);}return
0;
case -1:if(N==*_)return 36[_+Z] ;else return
main(Z,_-Z,N); }return
main(Z-Z,"cd0D5{.5xd=GdU>dD=U5|=+Ed{.dD..1tll*+=%19b"
"*==*B5b0=Ul*+=%1l0=U1bB{G*b0uul}+=|95h3+Ul.D+ {xl3xw;seif{w"
"3;f3 edo",N);}

That's C, mind you.

Since we started switching languages, I could've whipped out
my Perl, and wouldn't THAT be horrible. But I won't. It's
off-topic here.

(Translation: I'm chickening out!)

 

[Triple-DES]

Please can any of you guys write this program for me .

Sure, why not.

#include <stdexcept>
#include <string>
#include <iostream>
#include <istream>
#include <ostream>
#include <sstream>
using namespace std;
#define m 1<<8
#define si signed int
#define sz size
#define sb substr
#define st string
#define ss istringstream
#define cc(y) c<t,(l-y>0?l-y:1)>
template<class t,si l> class c{
  public:t s_,z_;cc(2)*t_;si b_,l_;
  static t*p(t s){t x;x=l==1?s:*cc(1):(s);
    return new t(t(x.sz()<l?" ":"")+x);}
  c(t s,si n=0)
    :s_(s),z_(*c<t,m>:(s)),b_(1),l_(!n?s.sz():n){
    try{t_=new cc(2)(s_.sb(1,s_.sz()-2),l_);}
    catch(out_of_range e){b_=!b_;}}
  virtual ~c(){if(b_)delete t_;}
  void operator[](si x){(*this)(x);if(b_)(*t_)[!b_];}
  void operator()(si x){if(b_&&x)(*t_)(x);
    if(l_!=l)cout<<z_.sb(z_.sz()-l_)<<endl;}};
int main(){st g,w;getline(cin,g);si i;cin>>i;ss k(g);
while(i--){k>>w;}c<st,m>o(w);o[1];}

There you go.

Good one! I really like how you involve so many c++ features in your
code. I don't think I can top this.

 

[Pavel Lepin]

Please can any of you guys write this program for me .

#include <stdexcept>
#include <string>
#include <iostream>
#include <istream>
#include <ostream>
#include <sstream>
using namespace std;
#define m 1<<8
#define si signed int
#define sz size
#define sb substr
#define st string
#define ss istringstream
#define cc(y) c<t,(l-y>0?l-y:1)>
template<class t,si l> class c{
public:t s_,z_;cc(2)*t_;si b_,l_;
static t*p(t s){t x;x=l==1?s:*cc(1):(s);
return new t(t(x.sz()<l?" ":"")+x);}
c(t s,si n=0)
:s_(s),z_(*c<t,m>:(s)),b_(1),l_(!n?s.sz():n){
try{t_=new cc(2)(s_.sb(1,s_.sz()-2),l_);}
catch(out_of_range e){b_=!b_;}}
virtual ~c(){if(b_)delete t_;}
void operator[](si x){(*this)(x);if(b_)(*t_)[!b_];}
void operator()(si x){if(b_&&x)(*t_)(x);
if(l_!=l)cout<<z_.sb(z_.sz()-l_)<<endl;}};
int main(){st g,w;getline(cin,g);si i;cin>>i;ss k(g);
while(i--){k>>w;}c<st,m>o(w);o[1];}

Good one!

Thank you for your kind words.

I really like how you involve so many c++ features in your
code.

"Abuse", you mean. Note how many template classes the
compiler instantiates. And how many std::strings are
instantiated at run-time (and never released). Catching
std:ut_of_range to stop recursion is pretty damn evil
too - I didn't even know I had it in me. I almost hope the
OP submits this to his instructor.

 

[James Kanze]

On 21 Feb, 10:31, (e-mail address removed) wrote:

[Obvious homework problem deleted...]

Sure, here you go:

#include <iostream>
#include <string>
#include <vector>
#include <algorithm>
using namespace std;
ostream& o = cout;
istream& i = cin;
typedef string s;
typedef vector<s> v;
typedef s::iterator si;
typedef size_t t;
#define b_ begin()
#define e_ end()
int main() {
s s_; v v_; t n;
getline(i,s_);
i>>n;
while(--n) s_ = s(find(s_.b_, s_.e_,' ')+1,s_.e_);
s_ = s(s_.b_,find(s_.b_,s_.e_,' '));
t d = 0u;
t ll = s_.size();
for(t l = ((ll ^ 1u) & 1u) + 1; l <= ll {
si b = s_.b_ + (ll - l) / 2;
o<< s(b, b + l) << "\n";
l += 2 - d;
if(l >= ll) d = 4u;
}}

Beautiful. It really pleases me to see that someone here has
finally learned how to respond to homework requests with some
originality.