need if (event.keyCode expert

[Julia Briggs]

Hi, can someone help me put together a if (event.keyCode function, that
will detect when the # character is pressed twice, and then
dosomething() ?

Sincerely,

%Julia%

 

[Evertjan.]

Julia Briggs wrote on 19 mrt 2005 in comp.lang.javascript:

Hi, can someone help me put together a if (event.keyCode function, that
will detect when the # character is pressed twice, and then
dosomething() ?

<script type='text/javascript'>

var n=0

function x(){
if(event.keyCode==35){
n+=1
if (n==2)alert('2 x #')
}
}

</script>


<input onkeypress='x()'>

 

[Randy Webb]

Julia Briggs wrote on 19 mrt 2005 in comp.lang.javascript:




<script type='text/javascript'>

var n=0

function x(){
if(event.keyCode==35){
n+=1
if (n==2)alert('2 x #')

if (n==2){alert('2 x #');n = 0}

better maybe?

 

[Lee]

Randy Webb said:

if (n==2){alert('2 x #');n = 0}

better maybe?

Better, but without knowing what the OP really wants to detect,
we don't know if it really does the job. If it's to prevent two
#'s from being entered in a single field, for example, it would
have to check the whole field value after each keystroke.

And of course, it would be much better to audit for that onchange.

 

[Evertjan.]

Randy Webb wrote on 19 mrt 2005 in comp.lang.javascript:

if (n==2){alert('2 x #');n = 0}

better maybe?

No, I dont think so.

Why improve on a OQ we don't know the reason of.

================

Perhaps two or more consecutive #'es are ment,
but also that is not asked.

function x(){
if(event.keyCode==35) n++ else n=0
if (n>=2) alert('2 or more #\'s consecutive')
}

 

[Lee]

Evertjan. said:

Randy Webb wrote on 19 mrt 2005 in comp.lang.javascript:


No, I dont think so.

Why improve on a OQ we don't know the reason of.

Why try to guess at answers to an OQ you don't understand?

 

[Evertjan.]

Lee wrote on 19 mrt 2005 in comp.lang.javascript:

Why try to guess at answers to an OQ you don't understand?

It is quite possible to understand a Q
without understanding for what purpose that Q is asked.

Improving on such Q however is out of the Q, Lee. ;-)