new operator - difference in usage?

[WittyGuy]

Is there any difference between the following two snippets of code?

snippet1:
int main()
{
int* p = new int(5); // With argument for initialising p to the
value 5
....
....
....
delete p;
return 0;
}

snippet2:

int main()
{
int* p = new int; // Simply allocate memory in free store for p
*p = 5;
....
....
....
delete p;
return 0;
}

thanks,
--Wg-

 

[n2xssvv g02gfr12930]

Is there any difference between the following two snippets of code?

snippet1:
int main()
{
int* p = new int(5); // With argument for initialising p to the
value 5
....
....
....
delete p;
return 0;
}

snippet2:

int main()
{
int* p = new int; // Simply allocate memory in free store for p
*p = 5;
....
....
....
delete p;
return 0;
}

thanks,
--Wg-

Functionally no. Which form you prefer is up to you, personally I prefer
the first because it tends to be more universal when using objects.

JB

 

[Richard Herring]

Is there any difference between the following two snippets of code?

snippet1:
int main()
{
int* p = new int(5); // With argument for initialising p to the
value 5
....
....
....
delete p;
return 0;
}

snippet2:

int main()
{
int* p = new int; // Simply allocate memory in free store for p
*p = 5;
....
....
....
delete p;
return 0;
}

For primitive types like int, there's no observable difference.

For class types, the effects may be different, because the first invokes
the copy constructor, the second uses the default constructor followed
by the assignment operator.