Newbie question about list method remove

[Sean Berry]

Why is this:

li2 =['this.txt', 'that.txt', 'April04', 'more.txt']
for item in li2:

if ".txt" in item:
li2.remove("%s" %item)['that.txt', 'April04']

I would think that 'that.txt' would be removed as well. Where am I wrong?

TIA

 

[news-server.sdd.hp.com]

Try this,

li2 =['this.txt', 'that.txt', 'April04', 'more.txt']
for item in li2[:]: #Make a copy of the list

if ".txt" in item:
li2.remove("%s" %item)['that.txt', 'April04']

Mike

Why is this:

li2 =['this.txt', 'that.txt', 'April04', 'more.txt']
for item in li2:

if ".txt" in item:
li2.remove("%s" %item)['that.txt', 'April04']

I would think that 'that.txt' would be removed as well. Where am I wrong?

TIA

 

[Larry Bates]

In Python you must think "differently" than in
other programming languages.

li2=[f for f in li2 if not f.endswith('.txt')]

for your specific example or in Python 2.2 and earlier

li2=[f for f in li2 if f.count('.txt') == 0]

for the more general .txt ANYWHERE in the string

or in Python 2.3

li2=[f for f in li2 if not '.txt' in f]


Larry Bates
Syscon, Inc.

Why is this:

li2 =['this.txt', 'that.txt', 'April04', 'more.txt']
for item in li2:

if ".txt" in item:
li2.remove("%s" %item)['that.txt', 'April04']

I would think that 'that.txt' would be removed as well. Where am I wrong?

TIA