Newbie question about multiple assignments

[Alex]

irb(main):091:0> a=1
=> 1
irb(main):092:0> b=2
=> 2
irb(main):093:0> a,b=b,a
=> [2, 1]
irb(main):094:0> a=1
=> 1
irb(main):095:0> b=2
=> 2
irb(main):096:0> a, b = b, a = a, b
=> [2, 1, 2] <-- Why?

What is the order for the assignments

 

[David Vallner]

To your why, another why: why do you need to use multiple parallel =20
assignments in one statement? That said, parallel assignments are somewha=
t =20
known to be a rather messy bit of syntax I'm apparently not as savvy with=
=20
as I thought, since I can't make heads or tails of what is really =20
happening.

My personal tip woukd be that the assignments are associative =20
right-to-left, and only the leftmost assignment is evaluated as a paralle=
l =20
one.

What probably happens is broken down into simpler statements:

a =3D a, b # a =3D=3D [1, 2]
a, b =3D b, *a # a =3D=3D2, b=3D=3D1

where the return value of the expression is the rvalue.

So the end values are what you expect, just the return value of the =20
expression isn't.

Hint: it's easy to avoid obscure syntax, so do that if possible. Noone =20
really admires godawful one-liners from hell in code he expects to =20
understand a week after writing it, even if there is a certain charm to =20
getting things done with them

Also, parallel assignment syntax is undergoing certain subtle, but =20
significant changes that seem to resolve some of the ambiguity - you migh=
t =20
want to look on one of the webpages that summarize changes in Ruby 1.9.

David Vallner

 

[Michael Ulm]

irb(main):091:0> a=1
=> 1
irb(main):092:0> b=2
=> 2
irb(main):093:0> a,b=b,a
=> [2, 1]
irb(main):094:0> a=1
=> 1
irb(main):095:0> b=2
=> 2
irb(main):096:0> a, b = b, a = a, b
=> [2, 1, 2] <-- Why?

What is the order for the assignments

Keep in mind, that

a, b = c, d

is just shorthand for

a, b = [c, d]

So, your expression

a, b = b, a = a, b

gets parsed as

a, b = [b, a = a, b]

and thus produces the observed behaviour.

HTH,

Michael


--
Michael Ulm
R&D Team
ISIS Information Systems Austria
tel: +43 2236 27551-219, fax: +43 2236 21081
e-mail: (e-mail address removed)
Visit our Website: www.isis-papyrus.com

 

[David Vallner]

irb(main):091:0> a=3D1
=3D> 1
irb(main):092:0> b=3D2
=3D> 2
irb(main):093:0> a,b=3Db,a
=3D> [2, 1]
irb(main):094:0> a=3D1
=3D> 1
irb(main):095:0> b=3D2
=3D> 2
irb(main):096:0> a, b =3D b, a =3D a, b
=3D> [2, 1, 2] <-- Why?
What is the order for the assignments

Keep in mind, that

a, b =3D c, d

is just shorthand for

a, b =3D [c, d]

So, your expression

a, b =3D b, a =3D a, b

gets parsed as

a, b =3D [b, a =3D a, b]

and thus produces the observed behaviour.

HTH,

Michael

That doesn't seem to explain the return value [2, 1, 2] of the expression=

 

[Karl Allmark]

irb(main):091:0> a=1
=> 1
irb(main):092:0> b=2
=> 2
irb(main):093:0> a,b=b,a
=> [2, 1]
irb(main):094:0> a=1
=> 1
irb(main):095:0> b=2
=> 2
irb(main):096:0> a, b = b, a = a, b
=> [2, 1, 2] <-- Why?
What is the order for the assignments

Keep in mind, that

a, b = c, d

is just shorthand for

a, b = [c, d]

So, your expression

a, b = b, a = a, b

gets parsed as

a, b = [b, a = a, b]

and thus produces the observed behaviour.

HTH,

Michael

That doesn't seem to explain the return value [2, 1, 2] of the expression.

David Vallner

Hi List

Just getting up to speed with ruby myself, try reading Davids explaination
as:

a, b = [b,(a = a), b]

Karl Allmark

 

[David Vallner]

Hi List

Just getting up to speed with ruby myself, try reading Davids =20
explaination
as:

a, b =3D [b,(a =3D a), b]

Karl Allmark

Not quite, what I had in mind would be this one-liner:

a, b =3D [b, *[a =3D [a, b]]]

I have a slight completely unfounded doubt the interpreter would =20
implicitly associate (a =3D a) in the middle of the expression.

The results observed in irb ARE however ambiguous with respect to both of=
=20
those possible interpretations.

David Vallner

 

[Karl Allmark]

-----Original Message-----
From: Karl Allmark [mailto:[email protected]]
Sent: 12 January 2006 14:07
To: ruby-talk ML
Subject: Re: Newbie question about multiple assignments

Alex wrote:
irb(main):091:0> a=1
=> 1
irb(main):092:0> b=2
=> 2
irb(main):093:0> a,b=b,a
=> [2, 1]
irb(main):094:0> a=1
=> 1
irb(main):095:0> b=2
=> 2
irb(main):096:0> a, b = b, a = a, b
=> [2, 1, 2] <-- Why?
What is the order for the assignments


Keep in mind, that

a, b = c, d

is just shorthand for

a, b = [c, d]

So, your expression

a, b = b, a = a, b

gets parsed as

a, b = [b, a = a, b]

and thus produces the observed behaviour.

HTH,

Michael

That doesn't seem to explain the return value [2, 1, 2] of the expression.

David Vallner

Hi List

Just getting up to speed with ruby myself, try reading Davids
explaination
as:

a, b = [b,(a = a), b]

Karl Allmark

Sorry I meant Micheal's explaination :-(

 

[Michael Ulm]

irb(main):091:0> a=1
=> 1
irb(main):092:0> b=2
=> 2
irb(main):093:0> a,b=b,a
=> [2, 1]
irb(main):094:0> a=1
=> 1
irb(main):095:0> b=2
=> 2
irb(main):096:0> a, b = b, a = a, b
=> [2, 1, 2] <-- Why?
What is the order for the assignments

Keep in mind, that

a, b = c, d

is just shorthand for

a, b = [c, d]

So, your expression

a, b = b, a = a, b

gets parsed as

a, b = [b, a = a, b]

and thus produces the observed behaviour.

That doesn't seem to explain the return value [2, 1, 2] of the expression.

Why not? the return value of an assignment is the right hand
side. In this case [2, 1 , 2]. The first and last value there
coming from b, and the middle value is the return value of the
assignment a = a.

Try this:

irb(main):001:0> a, b = [1, 2, 3, 4] # sets a=1 and b=2
=> [1, 2, 3, 4]

irb(main):002:0> a, b = [1, c = 2, 3] # sets a=1, b=2, and c = 2
=> [1, 2, 3]

HTH,

Michael








--
Michael Ulm
R&D Team
ISIS Information Systems Austria
tel: +43 2236 27551-219, fax: +43 2236 21081
e-mail: (e-mail address removed)
Visit our Website: www.isis-papyrus.com

 

[dblack]

Hi --

irb(main):091:0> a=1
=> 1
irb(main):092:0> b=2
=> 2
irb(main):093:0> a,b=b,a
=> [2, 1]
irb(main):094:0> a=1
=> 1
irb(main):095:0> b=2
=> 2
irb(main):096:0> a, b = b, a = a, b
=> [2, 1, 2] <-- Why?
What is the order for the assignments

Keep in mind, that

a, b = c, d

is just shorthand for

a, b = [c, d]

So, your expression

a, b = b, a = a, b

gets parsed as

a, b = [b, a = a, b]

and thus produces the observed behaviour.

HTH,

Michael

That doesn't seem to explain the return value [2, 1, 2] of the expression.

An assignment expression returns its right-hand side. In this case,
that's [b, a = a, b]:

a = 1
b = 2
[b, a = a, b] => [2,1,2]


David

--
David A. Black
(e-mail address removed)

"Ruby for Rails", from Manning Publications, coming April 2006!
http://www.manning.com/books/black

 

[David Vallner]

An assignment expression returns its right-hand side. In this case,
that's [b, a =3D a, b]:

a =3D 1
b =3D 2
[b, a =3D a, b] =3D> [2,1,2]


David

Ah well, for some strange reason I thought the parser would check for a =20
parallel assignment form inside the array constructor as well. Apparently=
=20
not... Right, that example pretty much clears the issue up.

David Vallner

 

[Andrew McGuinness]

An assignment expression returns its right-hand side. In this case,
that's [b, a = a, b]:

a = 1
b = 2
[b, a = a, b] => [2,1,2]

Ah well, for some strange reason I thought the parser would check for a
parallel assignment form inside the array constructor as well.
Apparently not... Right, that example pretty much clears the issue up.

Within method arguments, the "," gets parsed as an argument separator
not an array separator:

irb(main):094:0> puts( a,b = 1,2 )
1
1
2
=> nil
irb(main):095:0> puts( ( a,b = 1,2 ) )
1
2
=> nil



irb(main):103:0> a,b=1,2
=> [1, 2]
irb(main):104:0> a,b=(b,a=a,b)
=> [1, 2]
irb(main):105:0> a
=> 1
irb(main):106:0> b
=> 2

 

[dblack]

Hi --

An assignment expression returns its right-hand side. In this case,
that's [b, a = a, b]:

a = 1
b = 2
[b, a = a, b] => [2,1,2]


David

Ah well, for some strange reason I thought the parser would check for a
parallel assignment form inside the array constructor as well. Apparently
not... Right, that example pretty much clears the issue up.

The thing is, if you've got an array [a,b], and you add to it so that
it is [a,b,c=1], the meaning of the "a,b" part doesn't change; rather,
you're understood to have added an element. The comma semantics are
different in these different contexts, in other words.


David

--
David A. Black
(e-mail address removed)

"Ruby for Rails", from Manning Publications, coming April 2006!
http://www.manning.com/books/black