os.spawnl error

[Salvatore]

Hello,

Does someone already had ths problem ?
Traceback (most recent call last):
File "<stdin>", line 1, in ?
File "C:\Python24\lib\os.py", line 565, in spawnl
return spawnv(mode, file, args)
OSError: [Errno 22] Invalid argument

Regards

Salvatore

 

[Fredrik Lundh]

Does someone already had ths problem ?
Traceback (most recent call last):
File "<stdin>", line 1, in ?
File "C:\Python24\lib\os.py", line 565, in spawnl
return spawnv(mode, file, args)
OSError: [Errno 22] Invalid argument

that string doesn't contain what you think:
c:\windows
otepad.exe

you can use "raw" string literals to get around this:

more here:

http://docs.python.org/tut/node5.html#SECTION005120000000000000000

</F>

 

[Larry Bates]

The backslashes in your path are being interpreted
as escape characters (e.g. \n is a newline).

Try instead:

os.spawnl(os.P_NOWAIT,r'c:\windows\notepad.exe')

or

os.spawnl(os.P_NOWAIT,'c:\\windows\\notepad.exe')

-Larry Bates

Hello,

Does someone already had ths problem ?


Traceback (most recent call last):
File "<stdin>", line 1, in ?
File "C:\Python24\lib\os.py", line 565, in spawnl
return spawnv(mode, file, args)
OSError: [Errno 22] Invalid argument

Regards

Salvatore

 

[utabintarbo]

I have found the judicious use of os.path.normpath(path) to be quite
useful as well.

Bob