overloading in c

J

Johnny

Hi,
I need a function like: config_write(key, value)

I am using gcc in linux.

But different keys associate with different types of values, ex. char,
long, char *,
One way is to provide different functions such as config_write_char(long
key, char value), config_write_buffer(long key, char *value)

But programmers will be happy if only one function is needed to write all
kinds of configuration items.

The following is my idea about this:

bool config_write(unsigned long key, ...)
{
va_list ap;
va_start(ap, key);
int a; char b; long c; double d; char *e;
switch(config_get_type(key)) {
case INT:
a = va_arg(ap, int);
...
break;
case BUFFER:
e = va_arg(ap, char *);
//process e;
break;
...
}
va_end(ap);
return TRUE;
}

Note: config_get_type(unsigned long key) is used to get the data type of a
key , enum will be returned. The data type of a configuration item will be
stored in a table.

But it has shortcomings: The compiler won't do type-checking for you. The
programmers need assure that the type of value they passed in is correct for
that config item

So I want to know how to use only one function: config_write, but still
let compiler do type-checking for me.

Thanks for your advice
 
R

Richard Bos

Johnny said:
I need a function like: config_write(key, value)
But different keys associate with different types of values, ex. char,
long, char *,
One way is to provide different functions such as config_write_char(long
key, char value), config_write_buffer(long key, char *value)
The following is my idea about this:

bool config_write(unsigned long key, ...)
But it has shortcomings: The compiler won't do type-checking for you. The
programmers need assure that the type of value they passed in is correct for
that config item

So I want to know how to use only one function: config_write, but still
let compiler do type-checking for me.

You cannot, in C. If you really need this, go to C++; in most
circumstances, the solution you already give would be sufficient.

Richard
 
K

Kasper Dupont

I don't have a solution for this problem, but I know
that gcc have some features that might come in handy.

It can do type checking of printf statements as long
as the format string is a constant. But that doesn't
seem general enough to apply in your case.

I tried to come up with something using typeof, a
bit of macro magic (including the # operator), nested
functions, and finally __PRETTY_FUNCTION__.
Unfortunately it seems __PRETTY_FUNCTION__ contains
only the necesarry information if you are using C++,
and there you don't have nested functions.

The closest I could come up with was a switch on
sizeof. But if two of the types you might be using
are of the same size, then that isn't of much help.


Here is the code. Can somebody suggest a fix? Or is
this really impossible?

#include <stdio.h>
#define config_write(key, value) do { \
char *__foobar (typeof(value) x) { \
return __PRETTY_FUNCTION__; \
} \
do_config_write(key,__foobar(value),value);\
} while(0)
void do_config_write(long key, char *type, ...)
{
printf("%ld: %s\n",key,type);
}
int main()
{
int foobar=42;
config_write(27,foobar);
return 0;
}
 
T

Tommi Johnsson

Kasper said:
I don't have a solution for this problem, but I know
that gcc have some features that might come in handy.

it can be found from gcc manual...

if (__builtin_types_compatible_p (typeof (x), int ))
my_int_func (x);
else if (__builtin_types_compatible_p (typeof (x), float ))
my_float_func (x);
 

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