pass 2-dim array as param

[Serve La]

Why doesn't this work?

void myfunc(char **arr)
{
for (int i = 0; i < 3; i++) // access violation
puts(arr);
}

int main(void)
{
char arr[3][2] = { "1", "2", "3" };

for (int i = 0; i < 3; i++)
puts(arr); // prints correctly

myfunc(arr);
return 0;
}

 

[Andreas Kahari]

Why doesn't this work?

void myfunc(char **arr)

void myfunc(char arr[][2])

[cut]

int main(void)
{
char arr[3][2] = { "1", "2", "3" };

[cut]


If arr in main is an array of string literals of a certain
length, then you need to recieve it as such in your function
as well, otherwise your function has no way of knowing how far
apart e.g. arr and arr[i + 1] are.

Not that [3] in 'char arr[3][2] = { "1", "2", "3" };' may be
shortened into [].

 

[Serve La]

If arr in main is an array of string literals of a certain
length, then you need to recieve it as such in your function
as well, otherwise your function has no way of knowing how far
apart e.g. arr and arr[i + 1] are.

ah yes, I see now. Thanks

 

[Default User]

Why doesn't this work?

http://www.eskimo.com/~scs/C-faq/q6.18.html




Brian Rodenborn