passing a thrown exception

[Aryeh.Friedman]

Lets say I have some method that basically says (this is a syntex
question so thats why I said basically):

public void assertError(Exception exception)
{
if (exception)
System.out.println("PASS");
else
System.out.println("FAIL");
}

and then need to do something like:

assertError(new file("bad file name")); // or anything else that will
throw an exception

how can I force the line that throws the exception to actual apss it to
assertError so I can see if their was an exception thrown or not.

--Aryeh

 

[James Westby]

Lets say I have some method that basically says (this is a syntex
question so thats why I said basically):

public void assertError(Exception exception)
{
if (exception)
System.out.println("PASS");
else
System.out.println("FAIL");
}

and then need to do something like:

assertError(new file("bad file name")); // or anything else that will
throw an exception

how can I force the line that throws the exception to actual apss it to
assertError so I can see if their was an exception thrown or not.

--Aryeh

If I understand what you're after correctly then this is my normal way
of acheiving it

try {
someMethodCallOrSimilarThatIWouldLikeToThrowAnException();
fail();
} catch (TheExceptionThatIWantToBeThrownHere e) {
pass();
}

I have seen it with the fail() after the catch block, which I think
would be more robust, but I haven't come across a situation that this
caused a problem in.

If you are doing lots of similar things then this can be wrapped up in a
method to simplify the test to a single line.

Hope this helps,


James

 

[Aryeh.Friedman]

Thanks... I was aware of the above techinque my question was how to
implement it as a single method (passing the statement that may or may
not throw an exception)

--Aryeh