D
Dan Jacobson
Is it no great loss that perl lacks the n of sh's "shift n"?
I suppose there are two cases, one where we are sure we can indeed
shift n times, use for (1..$n){shift @F} I suppose, and one where we are
worried we will run out of parameters.
I suppose there are two cases, one where we are sure we can indeed
shift n times, use for (1..$n){shift @F} I suppose, and one where we are
worried we will run out of parameters.