Pointer question?

[rattan]

Assume the following codce (line numbers of reference only, compiler
gcc-3.4):

1 int a[3] = {2, 2, 3}, **ptr;
2 int sumit(int **, int);

calling sumit:

3 sumit(&a, 3);
or
4 *ptr = a; sumit(ptr, 3);

call on line 3 produces incompatible type pointers warning
but on line 4 does not.

So, what is the difference between the two calls?

-ishwar

 

[Eric Sosman]

Assume the following codce (line numbers of reference only, compiler
gcc-3.4):

1 int a[3] = {2, 2, 3}, **ptr;
2 int sumit(int **, int);

calling sumit:

3 sumit(&a, 3);
or
4 *ptr = a; sumit(ptr, 3);

call on line 3 produces incompatible type pointers warning
but on line 4 does not.

So, what is the difference between the two calls?

This is Question 6.18 in the comp.lang.c Frequently
Asked Questions (FAQ) list

http://www.c-faq.com/

 

[Barry Schwarz]

Assume the following codce (line numbers of reference only, compiler
gcc-3.4):

1 int a[3] = {2, 2, 3}, **ptr;
2 int sumit(int **, int);

calling sumit:

3 sumit(&a, 3);
or
4 *ptr = a; sumit(ptr, 3);

While this may be correct syntactically, it invokes undefined
behavior.

call on line 3 produces incompatible type pointers warning
but on line 4 does not.

So, what is the difference between the two calls?

What is the type of a? What is the type of &a?


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