A
Andrej Prsa
Hi!
Why do I get a warning about incompatible pointer type if I try to assign
a pointer to the function with variable argument number:
int func (int argc, ...) ,
but everything is ok when I'm using a simple function like:
int func (int argc, char *whatever)
Can't I point to the function with variable number of arguments?
Best wishes,
Andrej
Why do I get a warning about incompatible pointer type if I try to assign
a pointer to the function with variable argument number:
int func (int argc, ...) ,
but everything is ok when I'm using a simple function like:
int func (int argc, char *whatever)
Can't I point to the function with variable number of arguments?
Best wishes,
Andrej