Possible to traverse the children of an element without specifying child element names?

[Matt]

Is it possible to traverse the values of children of an element, and
no need to specify
the children's element names in XSLT element?

The XML file can be

<bio>
<skills>
<languages>
<language>XML</language>
<language>Java</language>
</languages>
<databases>
<database>Oracle</database>
</databases>
</skills>
</bio>

Approach #1: This will just append all data in a sequence of strings,
not good
<UL>
<xsl:for-each select="/bio/skills">
<LI><xsl:value-of select="."/></LI>
</xsl:for-each>
</UL>

Approach #2: correct approach, but it's tedious to specify all element
names that
need to traverse
<UL>
<xsl:for-each select="/resume/skills">
<xsl:for-each select="languages/language">
<LI><xsl:value-of select="."/></LI>
</xsl:for-each>
<xsl:for-each select="databases/database">
<LI><xsl:value-of select="."/></LI>
</xsl:for-each>
</xsl:for-each>
</UL>

any ideas? please advise. thanks!!

 

[William Park]

Is it possible to traverse the values of children of an element, and
no need to specify
the children's element names in XSLT element?

The XML file can be

<bio>
<skills>
<languages>
<language>XML</language>
<language>Java</language>
</languages>
<databases>
<database>Oracle</database>
</databases>
</skills>
</bio>

Above is input. What output do you want?

 

[Ben Edgington]

Is it possible to traverse the values of children of an element, and
no need to specify
the children's element names in XSLT element?

The XML file can be

<bio>
<skills>
<languages>
<language>XML</language>
<language>Java</language>
</languages>
<databases>
<database>Oracle</database>
</databases>
</skills>
</bio>

Approach #2: correct approach, but it's tedious to specify all element
names that
need to traverse
<UL>
<xsl:for-each select="/resume/skills">
<xsl:for-each select="languages/language">
<LI><xsl:value-of select="."/></LI>
</xsl:for-each>
<xsl:for-each select="databases/database">
<LI><xsl:value-of select="."/></LI>
</xsl:for-each>
</xsl:for-each>
</UL>

any ideas? please advise. thanks!!

Does this help?

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:template match="/">
<ul>
<xsl:for-each select="bio/skills/*/*">
<li><xsl:value-of select="."/></li>
</xsl:for-each>
</ul>
</xsl:template>

</xsl:stylesheet>