problem using subprocess.call

[Alex Kachanov]

Hi!
running py module with the following code from shell:
__
dir=os.path.join(os.path.expanduser("~/domains/domain.com/html"),'test')
subprocess.call(['find',dir+" -name '*.zip' -execdir unzip {} \;"])
__
returns:
__
find: /home/clients/alex291_ftp0/domains/domain.com/html/test -name
'*.zip' -execdir unzip {} \;: No such file or directory
__

Maybe I should change some escape-symbols? Which of them?
Tricks with
r"..."
"""..."""
\\
didn't help...

 

[Fredrik Lundh]

running py module with the following code from shell:
__
dir=os.path.join(os.path.expanduser("~/domains/domain.com/html"),'test')
subprocess.call(['find',dir+" -name '*.zip' -execdir unzip {} \;"])

subprocess.call(["find", dir, "-name", "*.zip", "-execdir", "unzip", "{}", ";"])

</F>

 

[Alex Kachanov]

dir=os.path.join(os.path.expanduser("~/domains/domain.com/html"),'test')
subprocess.call(['find',dir+" -name '*.zip' -execdir unzip {} \;"])

subprocess.call(["find", dir, "-name", "*.zip", "-execdir", "unzip",
"{}", ";"])

Ok, thanks, it works.
But what's the difference? Why I can't pass all parameters as one string?

 

[Fredrik Lundh]

subprocess.call(["find", dir, "-name", "*.zip", "-execdir", "unzip", "{}", ";"])

Ok, thanks, it works.
But what's the difference? Why I can't pass all parameters as one string?

because there's no one around to split them up for you.

after all, that's the whole point of running another program without going though the
shell: what you pass in ends up, as is, in the other program's argument array.

</F>