problems binding a dictionary

[vida00]

this has to be a very silly thing.

I have a function foo taking a dictionary as parameters. i.e.: def
foo(**kwargs): pass
when I call foo(param1='blah',param2='bleh',param3='blih') everything
is fine.
but when I do:.... pass
....
I get:

Traceback (most recent call last):
File "<stdin>", line 1, in ?
TypeError: foo() takes exactly 0 arguments (1 given)

Why? how do I pass the dictionary *d* to foo()?
Thanks,

- Josh.

 

[vida00]

this has to be a very silly thing.

I have a function foo taking a dictionary as parameters. i.e.: def
foo(**kwargs): pass
when I call foo(param1='blah',param2='bleh',param3='blih') everything
is fine.
but when I do:
... pass
...

I get:

Traceback (most recent call last):
File "<stdin>", line 1, in ?
TypeError: foo() takes exactly 0 arguments (1 given)

Why? how do I pass the dictionary *d* to foo()?
Thanks,

- Josh.

I mean, short of defining as foo(*args), or foo(dict).

 

[Sam Pointon]

You're not 'exploding' the dict to the param1='blah' etc form - you-re
actually passing it in as a single dict object. To solve this, add a **
to the front of a dict you want to explode in a function, just as you'd
add a * to explode a sequence.

 

[Dody Suria Wijaya]

this has to be a very silly thing.

I have a function foo taking a dictionary as parameters. i.e.: def
foo(**kwargs): pass
when I call foo(param1='blah',param2='bleh',param3='blih') everything
is fine.
but when I do:
... pass
...

I get:

Traceback (most recent call last):
File "<stdin>", line 1, in ?
TypeError: foo() takes exactly 0 arguments (1 given)

Why? how do I pass the dictionary *d* to foo()?
Thanks,

- Josh.

simply because your parameter definition expect keyword parameter
passing, and you are passing a paramater by placement. You should call
the function like this:

f(mykey=d)

or, since d is dict, you could use d's key/vals as keyword parameter:
f(**d)

which equivalent to doing:
f(param1='blah',param2='bleh',param3='blih')