(pyqt) Parameters when connecting a signal to a method?

[exhuma.twn]

Some code:

----------------------------------------------------------------------

def foobar(w):
print w

QtCore.QObject,connect( my_line_edit,
QtCore.SIGNAL("returnPressed()"), foobar )

 

[Diez B. Roggisch]

Some code:

----------------------------------------------------------------------

def foobar(w):
print w

QtCore.QObject,connect( my_line_edit,
QtCore.SIGNAL("returnPressed()"), foobar )

----------------------------------------------------------------------


How can I get this to work so "foobar" prints out the sender of the
signal (i.e. my_line_edit)?

I _think_ there is a way to get the signals sender in Qt itself. But I'm
unsure how to get that.

Alternatively, you can use a closure to create a reference:

def foobar(source, w):
print w

def slotgen(source, slot):
def _slot(*args):
return slot(*((source,) + args))
return _slot

my_slot = slotgen(my_line_edit, foobar)

QtCore.QObject,connect( my_line_edit,
QtCore.SIGNAL("returnPressed()"), my_slot )

However, be careful to keep a reference to my_slot around! Otherwise, it
will be garbage collected!

diez

 

[exhuma.twn]

I _think_ there is a way to get the signals sender in Qt itself. But I'm
unsure how to get that.

Alternatively, you can use a closure to create a reference:

def foobar(source, w):
print w

def slotgen(source, slot):
def _slot(*args):
return slot(*((source,) + args))
return _slot

my_slot = slotgen(my_line_edit, foobar)

QtCore.QObject,connect( my_line_edit,
QtCore.SIGNAL("returnPressed()"), my_slot )

However, be careful to keep a reference to my_slot around! Otherwise, it
will be garbage collected!

diez

Thanks diez. This works
Although, I still have to digest *what* this closure does, but I will
leave this as an exercise to myself.