Python Programming Challenges for beginners?

A

astral orange

Hi-

I am reading the online tutorial along with a book I bought on Python.
I would like to test out what I know so far by solving programming
challenges. Similar to what O'Reilly Learning Perl has. I really
enjoyed the challenges at the end of the chapter and it really help me
test out if I was truly taking in the material like I should. Could I
get some suggestions on resources? Is there anywhere where I can go
online (for free or purchase) for programming problems? I am familiar
with sites like Code Chef...etc...but at this stage that is not the
right 'venue' for me. I mainly need challenges like the ones they have
in Learning Perl.

Thanks again for all the help,
457r0
 
N

n00m

[skip]

How about the next problem:
you are given string "s" (len(s) <= ~10000), in the string only
letters 'a'..'z'
Task: to count the number of all *different* substrings of "s"

Example:
s = 'abbaz'
Its different substrings are:
a
b
z
ab
bb
ba
az
abb
bba
baz
abbaz
==================
Answer: 11
 
W

Wolodja Wentland

Hi-

I am reading the online tutorial along with a book I bought on Python.
I would like to test out what I know so far by solving programming
challenges. Similar to what O'Reilly Learning Perl has. I really
enjoyed the challenges at the end of the chapter and it really help me
test out if I was truly taking in the material like I should. Could I
get some suggestions on resources? Is there anywhere where I can go
online (for free or purchase) for programming problems? I am familiar
with sites like Code Chef...etc...but at this stage that is not the
right 'venue' for me. I mainly need challenges like the ones they have
in Learning Perl.

Project Euler has already been pointed out to you, but I enjoyed solving
the riddles at:

http://www.pythonchallenge.com/

Enjoy! :)
--
.''`. Wolodja Wentland <[email protected]>
: :' :
`. `'` 4096R/CAF14EFC
`- 081C B7CD FF04 2BA9 94EA 36B2 8B7F 7D30 CAF1 4EFC

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J

John McMonagle

n00m said:
[skip]

How about the next problem:
you are given string "s" (len(s) <= ~10000), in the string only
letters 'a'..'z'
Task: to count the number of all *different* substrings of "s"

Example:
s = 'abbaz'
Its different substrings are:
a
b
z
ab
bb
ba
az
abb
bba
baz
abbaz
==================
Answer: 11

Way to fail dude.

You're missing some sub-strings.
 
N

n00m

Of course, if you take '~' literally (len(s) <= -10001) I reckon
you've got way too many :)

Jon.

Then better: len(s) < abs(~10000)

PS It's a hard problem; so let's leave it alone
 
J

J Kenneth King

astral orange said:
Hi-

I am reading the online tutorial along with a book I bought on Python.
I would like to test out what I know so far by solving programming
challenges. Similar to what O'Reilly Learning Perl has. I really
enjoyed the challenges at the end of the chapter and it really help me
test out if I was truly taking in the material like I should. Could I
get some suggestions on resources? Is there anywhere where I can go
online (for free or purchase) for programming problems? I am familiar
with sites like Code Chef...etc...but at this stage that is not the
right 'venue' for me. I mainly need challenges like the ones they have
in Learning Perl.

Thanks again for all the help,
457r0

http://www.pythonchallenge.com/

I find this one neat because it uses riddles rather than straight
math.
 
M

MRAB

n00m said:
[skip]

How about the next problem:
you are given string "s" (len(s) <= ~10000), in the string only
letters 'a'..'z'
Task: to count the number of all *different* substrings of "s"

Example:
s = 'abbaz'
Its different substrings are:
a
b
z
ab
bb
ba
az
abb
bba
baz abba
bbaz
abbaz
==================
Answer: 11
Answer: 13
 
P

Paul Rudin

n00m said:
Then better: len(s) < abs(~10000)

PS It's a hard problem; so let's leave it alone

what's hard? substrings of a string? If you don't care too much about
efficiency it's easy enough:

import itertools
def subs(s):
return set(itertools.chain(
s[i:j]
for i in xrange(len(s))
for j in xrange(i, len(s)+1)))
 
L

Lie Ryan

Then better: len(s)< abs(~10000)

PS It's a hard problem; so let's leave it alone

I'm not going to write it, but I guess a fairly efficient solution can
be written with using a Trie: http://en.wikipedia.org/wiki/Trie

and iterating over its items, including partial prefixes.

Worse case scenario for creating the tree would be O(n**2) where n =
length of string, and iterating the structure would take O(N) where N =
number of different substring.

for "abbaz", the data structure would be:
{'a': {'b': {'b': {'a': {'z': None}}},
'z': None,
},
'b': {'b': {'a': {'z': None}},
'a': {'z': None}},
},
'z': None,
}

iterating the structure:
a
ab
abb
abba
abbaz
az
b
bb
bba
bbaz
ba
baz
z
---
13 (not including '')

Now, this makes me interested. How efficient it would be when len(s) ==
10000... might as well write it and see. Take back what I said, give me
a minute...
 
J

jim-on-linux

I have used py2exe many times with success.

My current program is completing as expected but the
exe file fails to open.

The output file states that _imaging_gif is missing. I
can run the program ok with IDLE but after converting
with py2exe, the exe file just sits there.
I'm using 2.6 on win XP.

Any Ideas?

jim-on-linux
 
N

n00m

PS
My straightforward C++ solution got TLE...

#include <stdlib.h>
#include <stdio.h>
#include <string.h>
#include <ctype.h>
#include <math.h>
#include <time.h>
#include <iostream>
#include <vector>
#include <string>
using namespace std;

int main() {
//freopen("88.txt", "rt", stdin);
//freopen("99.txt", "wt", stdout);
int tcs;
string s;
cin >> tcs;
while (tcs-- > 0) {
cin >> s;
int n = s.size();
s = s + ' ';
vector< vector<int> > a(256);
int ans = 0;
for (int i = n - 1; i >= 0; --i) {
int lev = 0;
vector<int> p = a[s];
vector<int> q;
while (!p.empty()) {
q.clear();
++lev;
for (int j = 0; j < p.size(); ++j) {
if (s[p[j] + 1] == s[i + lev]) {
q.push_back(p[j] + 1);
}
}
p.swap(q);
}
a[s].push_back(i);
ans += n - i - lev;
}
cout << ans << endl;
}

return 0;
}
 
J

Jon Clements

Oooh, that *does* look like fun.

Only problem is (quoting Douglas Adams): "I love deadlines. I like the
whooshing sound they make as they fly by."

scipy is extremely useful to have installed, and if you get *really*
into it, then the sage library|system at http://sagemath.org is
*extremely* useful...

Jon.
 

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