question about namespacing in perl

[Khamis Abuelkomboz]

Hi

I'm trying to unterstand the namescoping of perl, I found the following example:

package B::Assembler;
....
sub B::Asmdata:UT_U8 {..}

How do you define the full namespaced sub name?
Is it B::Assembler::B::Asmdata:UT_U8 or only B::Asmdata:UT_U8 ?
How you would call the function PUT_U8 from outside and inside this package?

I think the subs following a package definition belong to this package.

thanks
khamis

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[Tassilo v. Parseval]

Also sprach Khamis Abuelkomboz:

I'm trying to unterstand the namescoping of perl, I found the following example:

package B::Assembler;
...
sub B::Asmdata:UT_U8 {..}

This is the function PUT_U8() living in the package (=namespace)
B::Asmdata.

How do you define the full namespaced sub name?
Is it B::Assembler::B::Asmdata:UT_U8 or only B::Asmdata:UT_U8 ?

It's the latter. Specifying namespaces can only ever happen in two ways:
Either unqualified (PUT_U8()) which will access the entry in the current
namespace (main:: if there is no explicit package-declaration) or fully
qualified (B::Asmdata:UT_U8()) which accesses the entry in B::Asmdata
regardless of the namespace the calling code lives in.

How you would call the function PUT_U8 from outside and inside this package?

From outside:

B::Asmdata:UT_U8()

From inside:

PUT_U8()
# or (although unnecessarily)
B::Asmdata:UT_U8()

Note that giving the full name works everywhere whereas accessing an
unqualified entry only works if that entry lives in the current
namespace.

I think the subs following a package definition belong to this package.

Yes, as long as they are not qualified. In your example above however
the package-declaration was overruled by the package-declaration in

sub B::Asmdata:UT_U8 {}

Tassilo