Question

[Venkat]

Hi All,

I have the following problem please help me in solving this.

#include <stdio.h>
main()
{
int i, n=20;
for(i=0;i<n; i--)
{
printf("-");
}
}

Only one character in the above needs to be modified such that the character
'-' will be printed 20 times.
People say there are 3 ways of doing it but i could figure out only one way
given below.

#include <stdio.h>
main()
{
int i, n=20;
for(i=0;i<n; n--)
{
printf("-");
}
}

Can someone crack the other 2 possibilities.


regards,
Venkat

 

[Niels Dybdahl]

Can someone crack the other 2 possibilities.

Here is one:

for(i=0;-i<n; i--)

 

[Venkat]

Here is one:

for(i=0;-i<n; i--)

Niels thanks for a quick response, the 2nd possibility

is for(i=0;i<n;n--)

we just need the 3rd one.

 

[Victor Bazarov]

Niels thanks for a quick response, the 2nd possibility

is for(i=0;i<n;n--)

we just need the 3rd one.

for(i=0;i+n; i--)

Victor

 

[Old Wolf]

#include <stdio.h>
main()
{
int i, n=20;
for(i=0;i<n; i--)
{
printf("-");
}
}

Only one character in the above needs to be modified such that the character
'-' will be printed 20 times.
People say there are 3 ways of doing it but i could figure out only one way
given below.

for(i=0;i<n; n--)

for (i=0;i+n; i--)

PS. I don't think "for (i=0;-i<n; i--)" counts because that is
adding a character, not changing one. Did you quote the original
problem exactly? If it were "for(i=0; i<n; i--)" then you could
change the space to a minus.

 

[Benjamin Dacko]

Niels thanks for a quick response, the 2nd possibility

is for(i=0;i<n;n--)

we just need the 3rd one.

Piece of cake:

#include <stdio.h>
main()
{
int i, n=20;
for(i=0;i+n; i--)
{
printf("-");
}
}

 

[Benjamin Dacko]

Niels thanks for a quick response, the 2nd possibility

is for(i=0;i<n;n--)

we just need the 3rd one.

#include <stdio.h>
main()
{
int i, n=20;
for(i=0;i+n; i--)
{
printf("-");
}
}