M
Michael B. Williams
Ooooopppps and sorry about the sniplet thanks again
/* and if this helps I using JCreator and j2sdk1.4.2_04 */
double
interest = .0575,
J = 0,
N = 360, /* I had zero */
ftemp;
J = interest / 1200 ;
ftemp = ( 1-(1+J) );
N = N * (-1);
// N would be -360
System.out.println( Math.pow( ftemp , N ) );
My result is 1.0, which seems reasonable to me since your exponent is -0.0:
is this the exact code that produces Infinity? By my reckoning, x^(-y) ==
1/(x^y), so you have ftemp^(-0) == 1/(ftemp^0) == 1/1 == 1. The expected
When I compile and run your code, I get 1.0 as the answer, not Infinity.
That's the result I'd expect. If you're still getting 1.0, then I
suspect that's not the code that you're compiling or running. Are you
sure you aren't running an older version of the code by mistake?
--
www.designacourse.com
The Easiest Way to Train Anyone... Anywhere.
Chris Smith - Lead Software Developer/Technical Trainer
MindIQ Corporation
/* and if this helps I using JCreator and j2sdk1.4.2_04 */
double
interest = .0575,
J = 0,
N = 360, /* I had zero */
ftemp;
J = interest / 1200 ;
ftemp = ( 1-(1+J) );
N = N * (-1);
// N would be -360
System.out.println( Math.pow( ftemp , N ) );
Michael B. Williams said:Please help
The Math.pow call is retuning Infinity? What am I doing wrong - be
gental I java newbie. Thanks in advance
import java.math.*;
double
interest = .0575,
J = 0,
N = 0,
ftemp;
J = interest / 1200 ;
ftemp = ( 1-(1+J) );
N = N * (-1);
System.out.println( Math.pow( ftemp , N ) );
My result is 1.0, which seems reasonable to me since your exponent is -0.0:
is this the exact code that produces Infinity? By my reckoning, x^(-y) ==
1/(x^y), so you have ftemp^(-0) == 1/(ftemp^0) == 1/1 == 1. The expected
The Math.pow call is retuning Infinity? What am I doing wrong - be
gental I java newbie. Thanks in advance
When I compile and run your code, I get 1.0 as the answer, not Infinity.
That's the result I'd expect. If you're still getting 1.0, then I
suspect that's not the code that you're compiling or running. Are you
sure you aren't running an older version of the code by mistake?
--
www.designacourse.com
The Easiest Way to Train Anyone... Anywhere.
Chris Smith - Lead Software Developer/Technical Trainer
MindIQ Corporation