Regular expressions question

A

ASP.Confused

Ok. I have the following regular expression:

re.Pattern = "style[^=]*=[^\""]*\""[^\""]*\"""

It will grab any style attribute within HTML that uses double quotes, and
put it in the re.Matches collection.

Now, I want to include single quotes into this regular expression. Here's
what I have so far:

re.Pattern = "style[^=]*=[^\""']*(\""|\')[^\1]*\1"

but it does not work. Got any suggestions?
 
C

Chris Hohmann

ASP.Confused said:
Ok. I have the following regular expression:

re.Pattern = "style[^=]*=[^\""]*\""[^\""]*\"""

It will grab any style attribute within HTML that uses double quotes, and
put it in the re.Matches collection.

Now, I want to include single quotes into this regular expression. Here's
what I have so far:

re.Pattern = "style[^=]*=[^\""']*(\""|\')[^\1]*\1"

but it does not work. Got any suggestions?

style\s*=\s*('[^']*'|"[^"]*")
 
A

ASP.Confused

Ok...I feel stupid now....I didn't realize it was that easy....


Chris Hohmann said:
ASP.Confused said:
Ok. I have the following regular expression:

re.Pattern = "style[^=]*=[^\""]*\""[^\""]*\"""

It will grab any style attribute within HTML that uses double quotes, and
put it in the re.Matches collection.

Now, I want to include single quotes into this regular expression. Here's
what I have so far:

re.Pattern = "style[^=]*=[^\""']*(\""|\')[^\1]*\1"

but it does not work. Got any suggestions?

style\s*=\s*('[^']*'|"[^"]*")
 
C

Chris Hohmann

ASP.Confused said:
Ok...I feel stupid now....I didn't realize it was that easy....


Chris Hohmann said:
ASP.Confused said:
Ok. I have the following regular expression:

re.Pattern = "style[^=]*=[^\""]*\""[^\""]*\"""

It will grab any style attribute within HTML that uses double quotes, and
put it in the re.Matches collection.

Now, I want to include single quotes into this regular expression. Here's
what I have so far:

re.Pattern = "style[^=]*=[^\""']*(\""|\')[^\1]*\1"

but it does not work. Got any suggestions?

style\s*=\s*('[^']*'|"[^"]*")

Here's another, if you're itching to use a back reference:

style\s*=\s*('|").*?\1
 

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