Remove integer from float number

[Derek Basch]

How can I return:

".666"

from float:

"0.666"

This is what I have so far:

Thanks Everyone,
Derek Basch

 

[Larry Bates]

How can I return:

".666"

from float:

"0.666"

This is what I have so far:


Thanks Everyone,
Derek Basch

This works but I'm not entirely sure I know what you are
trying to accomplish.

("%.3f" % x)[1:]


-Larry Bates

 

[Derek Basch]

Ahh yes you have to put parenthases around the string formatting to
remove the integer using indexes. Thanks, that's just what I needed!

Derek Basch

 

[Paul Rubin]

Ahh yes you have to put parenthases around the string formatting to
remove the integer using indexes. Thanks, that's just what I needed!

I think it's better to remove leading zeros explicitly:

('%.3x' % x).lstrip('0')

 

[John Machin]

How can I return:

".666"

from float:

"0.666"

This is what I have so far:



Thanks Everyone,
Derek Basch

This works but I'm not entirely sure I know what you are
trying to accomplish.

("%.3f" % x)[1:]

>>> x = 12345.666; ("%.3f" % x)[1:] '2345.666'
>>>

I'm sure of neither what the OP is trying to accomplish nor what Larry's
definition of "works" is

Perhaps the condition abs(x) < 1.0 is implied ...

 

[Larry Bates]

How can I return:

".666"

from float:

"0.666"

This is what I have so far:


"%.6f" % x

Thanks Everyone,
Derek Basch

This works but I'm not entirely sure I know what you are
trying to accomplish.

("%.3f" % x)[1:]

x = 12345.666; ("%.3f" % x)[1:] '2345.666'

I'm sure of neither what the OP is trying to accomplish nor what Larry's
definition of "works" is

Perhaps the condition abs(x) < 1.0 is implied ...

For the example given, my code works. With so little information
the only thing I could do is answer the specific question and
caveat it that I don't know "exactly" what OP is trying to accomplish.
By the OPs response to my post, it was what he was looking for.
But I agree it is very much an edge-case question.

-Larry Bates

 

[Arne Ludwig]

With that terse description and the subject line I would interpret the
OP like so:
..666

 

[Grant Edwards]

With that terse description and the subject line I would interpret the
OP like so:

.666

Or if you're allergic to regular expressions:

print "." + "0.666".split(".")[-1] ..666
print "." + "123.666".split(".")[-1] ..666