Removing a single level of array nesting.

[Kenosis]

Greetings Rubyologists,

Suppose we have a simple array of arrays, e.g., [[1], [2], [3]]. What
would be the cleanest way, if it's possible, to remove the outter level
of array nesting such that the result is (a) a list of arrays: [1],
[2], [3], and (b) suitable for passing as a list of arrays to
GetoptLong. Thanks in advance for any help you can lend.

Ken

 

[Robert Klemme]

Greetings Rubyologists,

Suppose we have a simple array of arrays, e.g., [[1], [2], [3]]. What
would be the cleanest way, if it's possible, to remove the outter level
of array nesting such that the result is (a) a list of arrays: [1],
[2], [3], and (b) suitable for passing as a list of arrays to
GetoptLong. Thanks in advance for any help you can lend.

Your array *is* already a "list" of arrays. Maybe you just need the
star operator. Consider

irb(main):001:0> def foo(*args) p args end
=> nil
irb(main):002:0> foo([[1],[2]])
[[[1], [2]]]
=> nil
irb(main):003:0> foo(*[[1],[2]])
[[1], [2]]
=> nil

Kind regards

robert

 

[Kenosis]

Thanks Robert - that's what I thought too but my test in irb failed.
Must be that I have to use *array when passing it to GetopLong.

Regards,

Ken

Greetings Rubyologists,

Suppose we have a simple array of arrays, e.g., [[1], [2], [3]]. What
would be the cleanest way, if it's possible, to remove the outter level
of array nesting such that the result is (a) a list of arrays: [1],
[2], [3], and (b) suitable for passing as a list of arrays to
GetoptLong. Thanks in advance for any help you can lend.

Your array *is* already a "list" of arrays. Maybe you just need the
star operator. Consider

irb(main):001:0> def foo(*args) p args end
=> nil
irb(main):002:0> foo([[1],[2]])
[[[1], [2]]]
=> nil
irb(main):003:0> foo(*[[1],[2]])
[[1], [2]]
=> nil

Kind regards

robert

 

[Robert Klemme]

Thanks Robert - that's what I thought too but my test in irb failed.
Must be that I have to use *array when passing it to GetopLong.

That's what I was insinuating.

robert