"require and subdirectories" problem

Tobias Peters · Sep 9, 2003

def import(what)
require File.join(File.dirname(caller[0]), what)
end

and use "import" instead of "require".

Recheis Meinrad · Sep 9, 2003

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hi,
consider a script foo.rb that contains the line

require './lib/lib.rb'

lib.rb contains the line:

require './lib/annother.rb'

it works.=20
(require 'annother.rb' doesn't work allthough the file annother.rb is =
placed in the same directory as lib.rb)

but i am not very pleased with it. the library in the directory lib, =
must not know from where it is required.
what can i do so that lib can require all it's files no matter where the =
script that requires lib.rb is located?

- henon

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hi,

 consider a script foo.rb that contains =
the line


require './lib/lib.rb'


lib.rb contains the line:


require './lib/annother.rb'


it works. 

 (require 'annother.rb'  doesn't =
work allthough the file annother.rb is placed in the same directory as =
lib.rb)


but i am not very pleased with it. the =
library in the directory lib, must not know from where it is =
required.

 what can i do so that lib can require =
all it's files no matter where the script that requires lib.rb is =
located?

 

- henon


</BODY>
</HTML>
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Idan Sofer · Sep 9, 2003

hi,
but i am not very pleased with it. the library in the directory lib, must
not know from where it is required. what can i do so that lib can require
all it's files no matter where the script that requires lib.rb is located?

One of the things I most like in Ruby, is that even core functionality can be
easily modified at run-time:

[start messy untested code]

alias :_oldrequire :require
def require(req)
if req=~/\//
splited=req.split('/')
req_file=splited.pop
req_path=splited.join('/')
oldpath=Dir.pwd
Dir.chdir req_path
ret=_oldrequire(req_file)
Dir.chdir oldpath
return ret
else
_oldrequire(req)
end
end

[end messy untested code]

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AW: "require and subdirectories" problem	0	Sep 9, 2003

"require and subdirectories" problem

Tobias Peters

Recheis Meinrad

Idan Sofer

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