right-shifting problem

[eli.hen]

Hi,

I want to combine 2 different bytes into an integer, so that 1 byte
will be to the left of the second byte.

example:
byte[2] b;
b[0] = 0xE5;
b[1] = 0x35;
I want to get the unsigned number of 0xE535 (=58677), so I did:
int num = (b[0] << 8) | b[1];
But I got the negative number -6859.

How can I get the desired result (58677)?

-thanks, Eli

 

[eli.hen]

Found the solution: ;-)

int num = (((int)b[0] & 0xFF) << 8) | ((int)b[1] & 0xFF)

 

[Roedy Green]

example:
byte[2] b;
b[0] = 0xE5;
b[1] = 0x35;
I want to get the unsigned number of 0xE535 (=58677), so I did:
int num = (b[0] << 8) | b[1];
But I got the negative number -6859.

How can I get the desired result (58677)?

see http://mindprod.com/jgloss/endian.html
http://mindprod.com/jgloss/unsigned.html

 

[Roedy Green]

int num = (((int)b[0] & 0xFF) << 8) | ((int)b[1] & 0xFF)

the int casts are not needed. & 0xff promotes a byte to int.