run runs away

[Nx]

Hello

I think my question is how to make
the script wait until it returns from a call to run()


Here is a code snippet:

# next lines calls python2.4 32 bit version
# from a script running in python2.3 64 bit version
run("python2.4", "dbviewmaster.py")
# I want the following only to run after
# running of python2.4 has finished
self.textBrowser1.reload
f = open(self.DBMETA,'r')
for self.getline in f.readlines():
self.textBrowser1.append(self.getline)
f.close()



Thanks for any hints how to do that.
Nx

 

[Fredrik Lundh]

Here is a code snippet:

# next lines calls python2.4 32 bit version
# from a script running in python2.3 64 bit version
run("python2.4", "dbviewmaster.py")
# I want the following only to run after
# running of python2.4 has finished
self.textBrowser1.reload
f = open(self.DBMETA,'r')
for self.getline in f.readlines():
self.textBrowser1.append(self.getline)
f.close()

Thanks for any hints how to do that.

what's "run" ?
Traceback (most recent call last):
File "<stdin>", line 1, in ?
NameError: name 'run' is not defined

</F>

 

[jepler]

"run" is not the name of a Python built-in function. That leaves
everyone but you somewhat in the dark about why it does or does not wait
for the created process to complete.

If you want a function that starts a new process and waits for it to
complete, you probably want to use os.spawnv(os.P_WAIT, ...).

Jeff

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[Nx]

Thanks for your reply !

I now realize , that the run() used in this
code stems from a def , which actually wraps
os.spawnv(os.P_WAIT, ...) in
a way that eliminates waiting....

I like this newsgroup as there are always
people who are less stumped than oneself.

Nx