B
Bo Lindbergh
perldoc perlthrtut says:
Does this mean that if more than one thread exists, the qx operator,
the system function, and the open function in pipe mode all have
undefined behaviour?
/Bo Lindbergh
Thinking of mixing fork() and threads? Please lie down and wait until
the feeling passes. Be aware that the semantics of fork() vary between
platforms. For example, some UNIX systems copy all the current threads
into the child process, while others only copy the thread that called
fork(). You have been warned!
Does this mean that if more than one thread exists, the qx operator,
the system function, and the open function in pipe mode all have
undefined behaviour?
/Bo Lindbergh