serach file for regexp, return if found?

N

notnorwegian

i want to search a document for a particular regexp and then store
that regexp to a file.

but search and match only returns matchobjects(what are those anyway?
i dont get what to do with them, do they contain true/false,
stringposition etc?)

how do i do:
for rows in file:
print regexp.find ## or something equiavlent
 
Y

Yves Dorfsman

i want to search a document for a particular regexp and then store
that regexp to a file.
but search and match only returns matchobjects(what are those anyway?
i dont get what to do with them, do they contain true/false,
stringposition etc?)
how do i do:
for rows in file:
print regexp.find ## or something equiavlent

Is this what you are trying to do:

for row in file('/etc/services'):
if re.match('^ssh', row):
print row


Yves.
http://www.SollerS.ca
 

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