Showing node-level members of a global set

[ion]

Hi! I'm struggling with doing this in an elegant way -- I'll get my
XSLT books out of storage this weekend, but for now I could use some
help.
<bedknob>
<broomstick>
<bippity>boppity</bippity>
</broomstick>
<broomstick>
<bippity>boppity</bippity>
<bippity>boo</bippity>
</broomstick>
</bedknob>
I'd like to get the complete list of bippities, then compare the
bippities of each broomstick to them, and make a mark for each present
member of the complete set of bippities in a particular broomstick,
like
<table>
<thead>
<tr>
<th>boppity
</th>
<th>boo
</th>
</tr>
</thead>
<tbody>
<tr>
<td>X
</td>
<td>
</td>
</tr>
<tr>
<td>X
</td>
<td>X
</td>
</tr>
</tbody>
</table>

OK. So, I use a Muenchian sort to get the unique list of bippities for
the thead element, but then to do the rows in the body, I have to go
through it again, and check each member against the set of present
values. I'm thinking of something like taking the intersection and
looking for count() = 2, but I'm having trouble making it happen.

Can you help me?

Ion

 

[Joris Gillis]

Hi,

Hi! I'm struggling with doing this in an elegant wayI'd like to get the
complete list of bippities, then compare the
bippities of each broomstick to them, and make a mark for each present
member of the complete set of bippities in a particular broomstick,
like

I have no idea if this will conform to your idea of elegance (it uses
plain dumb for-each loops), but this solution seems to work:

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xslutput method="xml" indent="yes"/>

<xsl:key name="b" match="bippity" use="."/>
<xsl:variable name="bip"
select="//*[generate-id()=generate-id(key('b',.)[1])]"/>

<xsl:template match="bedknob">
<table>
<thead>
<tr>
<xsl:for-each select="$bip">
<th><xsl:value-of select="."/></th>
</xsl:for-each>
</tr>
</thead>
<tbody>
<xsl:apply-templates select="broomstick"/>
</tbody>
</table>
</xsl:template>

<xsl:template match="broomstick">
<xsl:variable name="this" select="bippity"/>
<tr>
<xsl:for-each select="$bip">
<td>
<xsl:if test=".=$this">X</xsl:if>
</td>
</xsl:for-each>
</tr>
</xsl:template>

</xsl:stylesheet>


regards,

 

[ion]

Thanks, Joris, that works great.
Ion

Hi,

Hi! I'm struggling with doing this in an elegant wayI'd like to get the
complete list of bippities, then compare the
bippities of each broomstick to them, and make a mark for each present
member of the complete set of bippities in a particular broomstick,
like

I have no idea if this will conform to your idea of elegance (it uses
plain dumb for-each loops), but this solution seems to work:

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xslutput method="xml" indent="yes"/>

<xsl:key name="b" match="bippity" use="."/>
<xsl:variable name="bip"
select="//*[generate-id()=generate-id(key('b',.)[1])]"/>

<xsl:template match="bedknob">
<table>
<thead>
<tr>
<xsl:for-each select="$bip">
<th><xsl:value-of select="."/></th>
</xsl:for-each>
</tr>
</thead>
<tbody>
<xsl:apply-templates select="broomstick"/>
</tbody>
</table>
</xsl:template>

<xsl:template match="broomstick">
<xsl:variable name="this" select="bippity"/>
<tr>
<xsl:for-each select="$bip">
<td>
<xsl:if test=".=$this">X</xsl:if>
</td>
</xsl:for-each>
</tr>
</xsl:template>

</xsl:stylesheet>


regards,