sleep for lesser of two values

[Earle Clubb]

I have a loop that runs for a variable amount of time, as defined by
@duration. I need to re-execute the command every 15 seconds for the
length of @duration, which is a float and can have any value. Can
anyone think of a more elegant way to do this than the code below?

end_time = Time.now + @duration
while (t = Time.now) < end_time
# execute command
sleep((15 < (end_time - t)) ? 15 : (end_time - t))
end


Thanks,
Earle

 

[Pete Elmore]

I have a loop that runs for a variable amount of time, as defined by
@duration. I need to re-execute the command every 15 seconds for the
length of @duration, which is a float and can have any value. Can
anyone think of a more elegant way to do this than the code below?

end_time = Time.now + @duration
while (t = Time.now) < end_time
# execute command
sleep((15 < (end_time - t)) ? 15 : (end_time - t))
end

I don't know about elegant, but it's a little more easy to read
sleep [15, end_time - t].min
than the ?: business.

 

[Tim Hunter]

I have a loop that runs for a variable amount of time, as defined by
@duration. I need to re-execute the command every 15 seconds for the
length of @duration, which is a float and can have any value. Can
anyone think of a more elegant way to do this than the code below?

end_time = Time.now + @duration
while (t = Time.now) < end_time
# execute command
sleep((15 < (end_time - t)) ? 15 : (end_time - t))
end


Thanks,
Earle

sleep([15, end_time -t].min)

 

[MenTaLguY]

I have a loop that runs for a variable amount of time, as defined by
@duration. I need to re-execute the command every 15 seconds for the
length of @duration, which is a float and can have any value. Can
anyone think of a more elegant way to do this than the code below?

end_time = Time.now + @duration
while (t = Time.now) < end_time
# execute command
sleep((15 < (end_time - t)) ? 15 : (end_time - t))
end

Maybe:

sleep [ 15, end_time - t ].min

-mental