small problem !!!

[Rahul]

hi ,
i cant understand whats wrong with the following piece of code:-

main()
{
..
a=i++;
..
..
}

Well it works fine with my compiler. The old value of i is assigned to
a and then it gets incremented.
Can any one please help me out?
thanks.

 

[Clark Cox]

hi ,
i cant understand whats wrong with the following piece of code:-

main()
{
.
a=i++;
.
.
}

Well it works fine with my compiler. The old value of i is assigned to
a and then it gets incremented.

It just happens to work fine on your platform. You have no guarantee
whether the new value gets stored to i before or after the location of
a is calculated. They could even happen simultaneously.

Just don't do it.

 

[Christopher Benson-Manica]

i cant understand whats wrong with the following piece of code:-

main()

int main(void)

a=i++;

You've managed to ask FAQ 3.1 verbatim.

http://c-faq.com/expr/evalorder1.html

Please check the FAQ before asking more tiresome questions.

 

[Keith Thompson]

i cant understand whats wrong with the following piece of code:-
main()
{
.
a=i++;
.
.
}
Well it works fine with my compiler. The old value of i is assigned
to
a and then it gets incremented.

It just happens to work fine on your platform. You have no guarantee
whether the new value gets stored to i before or after the location of
a is calculated. They could even happen simultaneously.

It's worse than that. The statement invokes undefined behavior (as
the FAQ explains; see 3.1 and 3.9).