sscanf needed

[Uwe Mayer]

Hi,

I've got a ISO 8601 formatted date-time string which I need to read into a
datetime object.
Is there a shorter way than using regular expressions? Is there a sscanf
function as in C?

Thanks,
Uwe

 

[Fredrik Lundh]

I've got a ISO 8601 formatted date-time string which I need to read into a
datetime object.

Help on built-in function strptime in module time:

strptime(...)
strptime(string, format) -> struct_time

Parse a string to a time tuple according to a format specification.
See the library reference manual for formatting codes (same as
strftime()).

</F>

 

[Leif B. Kristensen]

Uwe Mayer skrev:

Hi,

I've got a ISO 8601 formatted date-time string which I need to read
into a datetime object.

Look up time.strptime, it does exactly what you want.

 

[Kent Johnson]

Hi,

I've got a ISO 8601 formatted date-time string which I need to read into a
datetime object.

Something like this (adjust the format to suit):
import datetime, time
dt = datetime.datetime(*time.strptime(data, "%Y-%m-%d %H:%M:%S")[:6])

Kent

 

[Andrew E]

Hi,

I've got a ISO 8601 formatted date-time string which I need to read into a
datetime object.
Is there a shorter way than using regular expressions? Is there a sscanf
function as in C?

in addition to the other comments...

I like re, because it gives me the most control. See below.


import re
import datetime

class Converter:

def __init__( self ):
self.isoPattern = re.compile( "(\d\d\d\d)-(\d\d)-(\d\d)[tT
](\d\d)\d\d)\d\d)" )

def iso2date( self, isoDateString ):
match = self.isoPattern.match( isoDateString )
if not match: raise ValueError( "Not in ISO format: '%s'" %
isoDateString )

return datetime.datetime(
int(match.group(1)),
int(match.group(2)),
int(match.group(3)),
int(match.group(4)),
int(match.group(5)),
int(match.group(6))
)

c = Converter()


def demo( iso ):
try:
date = c.iso2date( iso )
print "Input '%s' -> datetime: %s" % ( iso, date )
except ValueError, e:
print str(e)

demo( "2005-04-21T12:34:56" )
demo( "2005-04-21 12:34:57" )
demo( "2005-04-2 12:34:57" )

 

[Lee Harr]

Hi,

I've got a ISO 8601 formatted date-time string which I need to read into a
datetime object.
Is there a shorter way than using regular expressions? Is there a sscanf
function as in C?

in addition to the other comments...

I like re, because it gives me the most control. See below.


import re
import datetime

class Converter:

def __init__( self ):
self.isoPattern = re.compile( "(\d\d\d\d)-(\d\d)-(\d\d)[tT
](\d\d)\d\d)\d\d)" )

def iso2date( self, isoDateString ):
match = self.isoPattern.match( isoDateString )
if not match: raise ValueError( "Not in ISO format: '%s'" %
isoDateString )

return datetime.datetime(
int(match.group(1)),
int(match.group(2)),
int(match.group(3)),
int(match.group(4)),
int(match.group(5)),
int(match.group(6))
)

c = Converter()


def demo( iso ):
try:
date = c.iso2date( iso )
print "Input '%s' -> datetime: %s" % ( iso, date )
except ValueError, e:
print str(e)

demo( "2005-04-21T12:34:56" )
demo( "2005-04-21 12:34:57" )
demo( "2005-04-2 12:34:57" )

That's nice. We should get some code in to the module
so that it is simple to round-trip the default datetime
timestamps.