std::bitset construction with std::string question

[Dill Hole]

Can anyone tell me why

std::bitset<2> foo(std::string("01"))

initializes the bitset in reverse order, i.e.

foo[0]=true
foo[1]=false

I would expect the bitset to be initialized in string text order.

 

[John Harrison]

Can anyone tell me why

std::bitset<2> foo(std::string("01"))

initializes the bitset in reverse order, i.e.

foo[0]=true
foo[1]=false

I would expect the bitset to be initialized in string text order.

I wouldn't,

6 = 110 = 1*2^2 + 1*2^1 + 0*2^0 == foo[2] is 1, foo[1] is 1, foo[0] is 0.

In other words its a consequence of the fact that in English numbers the
most signficant digit goes first.

john

 

[Mike Wahler]

Can anyone tell me why

std::bitset<2> foo(std::string("01"))

initializes the bitset in reverse order, i.e.

foo[0]=true
foo[1]=false

I would expect the bitset to be initialized in string text order.

See John H's reply, then observe the output of:

cout << foo << '\n';

-Mike