strcpy(s, "ABC"); gives a warning why...

[gdotone]

#include <stdio.h>
#include <stdlib.h>

#define MAXSTRING 100


int main(int argc, const char * argv[])
{

char c = 'a', *p, s[MAXSTRING];

p = &c;
printf ("%c%c%c \n", *p, *p + 1, *p + 2);

strcpy(s, "ABC");
printf ( "%s %c%c%s\n", s, *s + 6, *s + 7, s + 1 );

strcpy(s, "she sells sea shells by the seashore" );
p = s + 14;

for ( ; *p != '\0'; ++p )
{
if ( *p == 'e' )
*p = 'E';

if ( *p == ' ' )
*p = '\n';
}

printf ( "%s\n\n", s );

return 0;
}

This program come from "A Book on C"
When I compile this program I get a warning from the compiler.

Implicitly declaring C library function 'strcpy' with type 'char*(char *, const char *)'

The compiler is LLVM 3.1

Why am I getting this warning? What does it mean? How can it be fixed so that there is no warning given?

Thanks, everyone.

 

[Ike Naar]

Implicitly declaring C library function 'strcpy' with type 'char*(char *, const char *)'

#include <string.h>

 

[gdotone]

#include &lt;stdio.h&gt;
#include &lt;stdlib.h&gt;

#define MAXSTRING 100


int main(int argc, const char * argv[])
{

char c = 'a', *p, s[MAXSTRING];

p = &amp;c;
printf (&quot;%c%c%c \n&quot;, *p, *p + 1, *p + 2);

strcpy(s, &quot;ABC&quot;
printf ( &quot;%s %c%c%s\n&quot;, s, *s + 6, *s + 7, s + 1 );

strcpy(s, &quot;she sells sea shells by the seashore&quot; );
p = s + 14;

for ( ; *p != '\0'; ++p )
{
if ( *p == 'e' )
*p = 'E';

if ( *p == ' ' )
*p = '\n';
}

printf ( &quot;%s\n\n&quot;, s );

return 0;
}

This program come from &quot;A Book on C&quot;
When I compile this program I get a warning from the compiler.

Implicitly declaring C library function 'strcpy' with type 'char*(char *, const char *)'

The compiler is LLVM 3.1

Why am I getting this warning? What does it mean? How can it be fixed so that there is no warning given?

Thanks, everyone.

 

[gdotone]

Thanks.

 

[Barry Schwarz]

#include &lt;stdio.h&gt;
#include &lt;stdlib.h&gt;

#define MAXSTRING 100


int main(int argc, const char * argv[])
{

char c = 'a', *p, s[MAXSTRING];

p = &amp;c;
printf (&quot;%c%c%c \n&quot;, *p, *p + 1, *p + 2);

strcpy(s, &quot;ABC&quot;
printf ( &quot;%s %c%c%s\n&quot;, s, *s + 6, *s + 7, s + 1 );

strcpy(s, &quot;she sells sea shells by the seashore&quot; );
p = s + 14;

for ( ; *p != '\0'; ++p )
{
if ( *p == 'e' )
*p = 'E';

if ( *p == ' ' )
*p = '\n';
}

printf ( &quot;%s\n\n&quot;, s );

return 0;
}

This program come from &quot;A Book on C&quot;
When I compile this program I get a warning from the compiler.

Implicitly declaring C library function 'strcpy' with type 'char*(char *, const char *)'

The compiler is LLVM 3.1

Why am I getting this warning? What does it mean? How can it be fixed so that there is no warning given?

Thanks, everyone.

You should be aware that the standard does not guarantee that 'a'+1, 'a'+2,'A'+6, or 'A'+7 represent printable characters. It is not a problen in the two common character sets (ASCII and EBCDIC). But in EBCDIC, 'A'+9 is not printable while it is in ASCII.