string as a function return type

[C@limero]

If I want to declare a function in a header file that returns a
string, I always get an error (something complaining about
a syntax error before an ')').

I have declared:



#ifndef MYHEADER_H
#define MYHEADER_H

string function(int day, int month, int year);

#endif



But then I get always an error from the compiler.

If I change this to

#ifndef MYHEADER_H
#define MYHEADER_H

const char* function(int day, int month, int year);

#endif

I get no error.

But the problem then is, since I use an std:stringstream oss in
the definition, I have to write "ugly" things like

return oss.str().c_str();

Is there a way to bypass this ?

 

[Victor Bazarov]

If I want to declare a function in a header file that returns a
string, I always get an error (something complaining about
a syntax error before an ')').

I have declared:



#ifndef MYHEADER_H
#define MYHEADER_H

string function(int day, int month, int year);

'string' is a typedef declared in <string> header. You need to include
that header before using 'string'. And use 'std::string' because the
name 'string' (the typedef) is declared in the 'std' namespace. So, the
line above should be replaced with two:

#endif



But then I get always an error from the compiler.

If I change this to

#ifndef MYHEADER_H
#define MYHEADER_H

const char* function(int day, int month, int year);

#endif

I get no error.

But the problem then is, since I use an std:stringstream oss in
the definition, I have to write "ugly" things like

return oss.str().c_str();

Is there a way to bypass this ?

No, there is no way to bypass it. It has to be resolved.

V

 

[Mike Smith]

If I want to declare a function in a header file that returns a
string, I always get an error (something complaining about
a syntax error before an ')').

I have declared:



#ifndef MYHEADER_H
#define MYHEADER_H

#endif

string is not a built-in type; it is a class, declared in header
<string>, and in namespace std.