String to character literal conversion

[-D]

Hi all,

How do you evaluate a string as unicode literal? That is,
how do you convert "\u004E" (normal string) to '\u004E' (character literal)?

Thanks!

- D

 

[Alan Moore]

Hi all,

How do you evaluate a string as unicode literal? That is,
how do you convert "\u004E" (normal string) to '\u004E' (character literal)?

char ch = (char)Integer.parseInt("\\u004E".substring(2), 16);

 

[Tor Iver Wilhelmsen]

How do you evaluate a string as unicode literal? That is,
how do you convert "\u004E" (normal string) to '\u004E' (character literal)?

If it's in source code, the resulting String will have 1 character;
you get that with

char ch = theString.charAt(0);

 

[Thomas Schodt]

How do you evaluate a string as unicode literal? That is,
how do you convert "\u004E" (normal string) to '\u004E' (character literal)?

The only way I can make any sense of your post is if you mean


public class Eval {
// note the double backslash
static final String normalString = "\\u004E";
static final char literalCharacter = evaluateString(normalString);

// argument must contain "\\uXXXX" exactly
// first is a backslash '\\', second is a lowercase 'u'
// ande XXXX is a unicode character id
static char evaluateString(String s) {
// insert code here
return (char)Integer.parseInt(s.substring(2),0x10);
}

public static void main(String[] arg) {
System.out.println(literalCharacter);
}
}


Improving the evaluateString() to take arguments of varying format
is left as an exercise for the OP.