B
bahoo
Hi,
I am using Windows + Python 2.5.
This line of code fails (see error message at the end),
last_line = subprocess.Popen(["D:/release/win.exe 0.5 1000 100 D:/
images/img.ppm out.ppm"], stdout=subprocess.PIPE).communicate()[0]
but using "os.system" works:
os.system('D:/release/win.exe 0.5 1000 100 D:/images/img.ppm out.ppm')
----------
C:/Python25/pythonw.exe -u "D:/run.pyw"
Traceback (most recent call last):
File "D:/run.pyw", line 59, in <module>
process_dir(mydir)
File "D:/run.pyw", line 52, in process_dir
segmentation (dir,f)
File "D:/run.pyw", line 35, in segmentation
last_line = subprocess.Popen(["D:/release/win.exe 0.5 1000 100 D:/
images/img.ppm out.ppm"], stdout=subprocess.PIPE).communicate()[0]
File "C:\Python25\lib\subprocess.py", line 593, in __init__
errread, errwrite)
File "C:\Python25\lib\subprocess.py", line 793, in _execute_child
startupinfo)
WindowsError: [Error 22] The filename, directory name, or volume label
syntax is incorrect
I am using Windows + Python 2.5.
This line of code fails (see error message at the end),
last_line = subprocess.Popen(["D:/release/win.exe 0.5 1000 100 D:/
images/img.ppm out.ppm"], stdout=subprocess.PIPE).communicate()[0]
but using "os.system" works:
os.system('D:/release/win.exe 0.5 1000 100 D:/images/img.ppm out.ppm')
----------
C:/Python25/pythonw.exe -u "D:/run.pyw"
Traceback (most recent call last):
File "D:/run.pyw", line 59, in <module>
process_dir(mydir)
File "D:/run.pyw", line 52, in process_dir
segmentation (dir,f)
File "D:/run.pyw", line 35, in segmentation
last_line = subprocess.Popen(["D:/release/win.exe 0.5 1000 100 D:/
images/img.ppm out.ppm"], stdout=subprocess.PIPE).communicate()[0]
File "C:\Python25\lib\subprocess.py", line 593, in __init__
errread, errwrite)
File "C:\Python25\lib\subprocess.py", line 793, in _execute_child
startupinfo)
WindowsError: [Error 22] The filename, directory name, or volume label
syntax is incorrect