Template member operators.

[Alan Woodland]

Is the following construct legal? If yes how does one actually call the
operator? I've tried quite a few variations on way of calling this, all
to no avail.

class Foo {
public:
template <typename T> const T& operator*() const
};

Thanks,
Alan

 

[Alan Woodland]

Appologies:

Alan Woodland wrote:
This line:

template <typename T> const T& operator*() const

Should read as:

template <typename T> const T& operator*() const;

Alan

 

[Kai-Uwe Bux]

Is the following construct legal? If yes how does one actually call the
operator? I've tried quite a few variations on way of calling this, all
to no avail.

class Foo {
public:
template <typename T> const T& operator*() const
};

class Foo {
public:
template <typename T> const T& operator*() const
{}
};

int main ( void ) {
Foo f;
f.operator*<int>();
}


Best

Kai-Uwe Bux

 

[Victor Bazarov]

[..]

class Foo {
public:
template <typename T> const T& operator*() const
{}

{ return T(); } // or something, otherwise it has UB

};

int main ( void ) {
Foo f;
f.operator*<int>();
}

V