D
dondora
hi there.
this is my homework. I've been trying to get some result but things
haven't been gone well.
Those are the nested loop. And What I have to do is to get time
complexity T(n) of the nested loop assuming n=2^k.
---------------------------------------------------------------------------------------------------------
for(i = 0; i<=n; i++) {
j = n;
while( j>= 1) {
<body of the while loop> // Needs Ï´(1)
j = j/2;
}
}
---------------------------------------------------------------------------------------------------------
What I got is T(n) = n{1 + (k+1)(Ï´(1) + 1_} assuming j=n and j=j/2
and Ï´(1) are unit operations.
So I did try to solve my result to get a neat expresion.
that's what I did
n=2^k => lg(n)=k
T(n) = n{1 + (k+1)(Ï´(1) + 1)}
= n{1 + (lg(n) + 1)(Ï´(1) + 1)}
= n{1 + lg(n)Ï´(1) + lg(n) + Ï´(1) + 1} // by distribution law
and
= n{1 + lg(n)Ï´(1) + lg(n) + Ï´(1)}
= n{1 + lg(n)Ï´(1) + Ï´(lg(n))}
= n{1 + Ï´(lg(n)) + Ï´(lg(n))}
= n{Ï´(lg(n)) + Ï´(lg(n))}
= n{Ï´(lg(n))} = nÏ´(lg(n)) = Ï´(nlg(n))
is that right? I wanna know where it's right or not.
I guess it has something wrong. So I need your help.
I appreciate your generous help.
ps : don't say to me 'do you own homework'. I already tried many times.
this is my homework. I've been trying to get some result but things
haven't been gone well.
Those are the nested loop. And What I have to do is to get time
complexity T(n) of the nested loop assuming n=2^k.
---------------------------------------------------------------------------------------------------------
for(i = 0; i<=n; i++) {
j = n;
while( j>= 1) {
<body of the while loop> // Needs Ï´(1)
j = j/2;
}
}
---------------------------------------------------------------------------------------------------------
What I got is T(n) = n{1 + (k+1)(Ï´(1) + 1_} assuming j=n and j=j/2
and Ï´(1) are unit operations.
So I did try to solve my result to get a neat expresion.
that's what I did
n=2^k => lg(n)=k
T(n) = n{1 + (k+1)(Ï´(1) + 1)}
= n{1 + (lg(n) + 1)(Ï´(1) + 1)}
= n{1 + lg(n)Ï´(1) + lg(n) + Ï´(1) + 1} // by distribution law
and
= n{1 + lg(n)Ï´(1) + lg(n) + Ï´(1)}
= n{1 + lg(n)Ï´(1) + Ï´(lg(n))}
= n{1 + Ï´(lg(n)) + Ï´(lg(n))}
= n{Ï´(lg(n)) + Ï´(lg(n))}
= n{Ï´(lg(n))} = nÏ´(lg(n)) = Ï´(nlg(n))
is that right? I wanna know where it's right or not.
I guess it has something wrong. So I need your help.
I appreciate your generous help.
ps : don't say to me 'do you own homework'. I already tried many times.