Unpacking a list of strings

[Panos Laganakos]

Is there some other practice than reading all the strings and slicing
them later?

They're stored in the form of:
List Group[10]:
char[17] name;

So I thought of doing:
unpacked = unpack('%s' % (10*17), data)

And then slicing the list by a step of 17.

Is there some way to have unpack return a tuple with each element
holding the name (char[17])?

 

[Alex Martelli]

Is there some other practice than reading all the strings and slicing
them later?

They're stored in the form of:
List Group[10]:
char[17] name;

So I thought of doing:
unpacked = unpack('%s' % (10*17), data)

And then slicing the list by a step of 17.

Is there some way to have unpack return a tuple with each element
holding the name (char[17])?

unpack by formatstring 10*'17s' ...


Alex