Unused variables used for class constructors

[artooro]

Hi,

I'm using some lines of code like this:
ClassName *var = new ClassName(...);

and that's it. The class constructor does everything I want (there are
methods to do more but I don't need them)
But this generates a warning (gcc4) saying it's an unused variable.
Is there a better way to do this?

 

[John Harrison]

Hi,

I'm using some lines of code like this:
ClassName *var = new ClassName(...);

and that's it. The class constructor does everything I want (there are
methods to do more but I don't need them)
But this generates a warning (gcc4) saying it's an unused variable.
Is there a better way to do this?

Well a better way is

ClassName var(...);

Why use new when you don't have to? Whether that gets rid of your
warning or not is another matter. Compiler warnings are often dubious.

john

 

[=?iso-8859-1?Q?Ali_=C7ehreli?=]

I'm using some lines of code like this:
ClassName *var = new ClassName(...);

and that's it. The class constructor does everything I want (there are
methods to do more but I don't need them)
But this generates a warning (gcc4) saying it's an unused variable.
Is there a better way to do this?

Even though g++ specific issues are off-topic here, I can come up with two
solutions:

int g_i = 0;

class ClassName
{
public:

ClassName(int i)
{
g_i += i; // everything I need
}
};

#include <iostream>

void do_it(ClassName const &)
{}

int main()
{
// one way
do_it(ClassName(1));

// another way
ClassName var(1) __attribute__((unused));
}

Ali

 

[artooro]

Well your suggestions which I have tried before but forgot about don't
work. It seems this class only work using this method. (wxWidgets
stuff)

No big problem though.

 

[Jay Nabonne]

Hi,

I'm using some lines of code like this:
ClassName *var = new ClassName(...);

and that's it. The class constructor does everything I want (there are
methods to do more but I don't need them)
But this generates a warning (gcc4) saying it's an unused variable.
Is there a better way to do this?

If you don't need the var, then don't use it:

new ClassName(...);

I'm assuming there's some reason you don't need to delete it (like it
deletes itself).

- Jay