use unintialized_copy where is initialized

[Stanley Rice]

`the difference between *uninitialized_copy* function and *copy* is that the
*uninitialized_copy* function could copy the object at the location where
is uninitialized. For example:

int ia[5] = {1, 2, 3, 4, 5};
int n = sizeof ia / sizeof *ia;
int *ib = (int *)malloc(n * sizeof *ia);
uninitialized_copy(ia, ia + n, ib);

My question is, what if I copy the initialized memory by calling the
uninitialized_copy function. Instead of allocatiing the memory by calling
malloc, I use new.
int *ib = new int[n];
uninitialized_copy(ia, ia + n, ib);

I works too. But am i correct? If so, what's the difference between copy
and uninitialized_copy?

Thanks.