A
Ayaz Ahmed Khan
Can a variable containing, say, an integer value be used as size
declarator for an array of integers? g++ does not complain, but other
compilers, such as Visual C++/6.0, Borland Builder C++, Turbo C++, and
Dev-C++/4.0, that I tested it on decline to use variables as size
declarators.
--
Ayaz Ahmed Khan
Yours Forever in, | Webmaster,
Cyberspace. | http://fast-ce.org/
_______________________________________________
I ditched Windows for Linux over two years ago.
Life's never been better since.
declarator for an array of integers? g++ does not complain, but other
compilers, such as Visual C++/6.0, Borland Builder C++, Turbo C++, and
Dev-C++/4.0, that I tested it on decline to use variables as size
declarators.
--
Ayaz Ahmed Khan
Yours Forever in, | Webmaster,
Cyberspace. | http://fast-ce.org/
_______________________________________________
I ditched Windows for Linux over two years ago.
Life's never been better since.